TLS Online TPP Program

#Question id: 15150


In this problem we will explore some of the many ways that mutations in two different genes can interact to produce different Mendelian ratios. Consider a hypothetical insect species that has red eyes. Imagine mutations in two different unlinked genes that can, in certain combinations, block the formation of red eye pigment yielding mutants with white eyes. In principle, there are two different possible arrangements for two biochemical steps responsible for the formation of red eye pigment. The two genes might act in series such that a mutation in either gene would block the formation of red pigment. Alternatively, the two genes could act in parallel such that mutations in both genes would be required to block the formation of red pigment.
Further complexity arises from the possibility that mutations in either gene that lead to a block in enzymatic activity could be either dominant or recessive. If the crosses is made between a wild type insect with red eyes and a true breeding white eyed strain with mutations in both genes. Such considerations yield the Pathways in series with recessive mutations in both genes, the F1 progeny shows will have red eye, what is the expected phenotypic ratio of red to white eyed insects in the F2.

#Unit 8. Inheritance Biology
  1. 9 red: 7 white
  2. 3 red : 1 white
  3. 13 red : 3 white
  4. 15 red : 1 white
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TLS Online TPP Program

#Question id: 2836

#Unit 2. Cellular Organization

The fact that a specific protein leaves a “footprint” on a DNA molecule is indicative of
a. a lack of interaction between the specific protein and DNA.
b. protection from DNAse by the specific protein.
c. binding of the specific protein to all types of DNA.
d. binding of the specific protein to a specific sequence of DNA.

TLS Online TPP Program

#Question id: 2837

#Unit 2. Cellular Organization

The C-terminal activation domain of transcriptional activators is capable of
a. binding to DNA.                 
b. stimulating transcription.
c. interaction with other transcriptional machinery.
d. functioning in a fusion with a DNA-binding domain from an unrelated transcriptional activator.

TLS Online TPP Program

#Question id: 2838

#Unit 2. Cellular Organization

You want to study the potential interaction between nucleosome-bound DNA and a specific histone deacetylase. You decide to perform an electrophoretic mobility shift assay (EMSA). You use a 32P end-labelled, linear template DNA that contains two nucleosome positioning sites. You assemble two nucleosomes on the DNA template before incubation with and without the histone deacetylase. For some reactions, you use unmodified nucleosomes. For other reactions, you use nucleosomes that are methylated at lysine 36 of the histone protein H3.

A. The histone deacetylase binds nucleosome bound-DNA in lanes 1, 2, 3, and 4.

B. The histone deacetylase binds nucleosome bound-DNA in lanes 3& 4.

C. The histone deacetylase seems to recognize methylated nucleosomes at lysine 36 of histone H3 in lane 1, 2 & 3 better than unmethylated nucleosomes in lane 4 &5

D. The histone deacetylase seems to recognize methylated nucleosomes at lysine 36 of histone H3 in lane 1 & 2 better than unmethylated nucleosomes in lane 3 &4

TLS Online TPP Program

#Question id: 2839

#Unit 2. Cellular Organization

Consider for correct match

I. All the different members of family of genes and proteins are sufficiently similar in sequence to suggest a common ancestral sequence.

A. Homologous

II. Sequences that presumably diverged as a result of gene duplication

B. Paralogous

III. Sequences that arose because of speciation

C. Orthologous

TLS Online TPP Program

#Question id: 2840

#Unit 2. Cellular Organization

An experimental setup provided the assay for identifying factors that facilitate transcription in the presence of chromatin. A factor called FACT (facilitates chromatin transcription) functions as 

TLS Online TPP Program

#Question id: 2841

#Unit 2. Cellular Organization

To duplicate a chromosome, at least half of the nucleosomes on the daughter chromosomes must be newly synthesized. But histone proteins as new and old occupies strands differently as