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#Question id: 12700
#Unit 7. System Physiology – Animal
A young man is found comatose, having taking an unknown number of sleeping pills an unknown time before. An arterial blood sample yields the following values: pH = 7.02, HCO3− = 14 mEq/L, and PCO2 = 68 mm Hg. This patient’s acid–base status is most accurately described as
TLS Online TPP Program
#Question id: 12701
#Unit 7. System Physiology – Animal
In chronic respiratory acidosis with partial renal compensation, you would expect to find the following changes, compared to normal:___ urinary excretion of NH4+; ______ plasma HCO3− concentration; and _____ urine pH.
TLS Online TPP Program
#Question id: 12702
#Unit 8. Inheritance Biology
Some given characteristics features of Cytoplasmic inheritance, which of the following statements are not follow the inheritance pattern;
a) Cytoplasmic gene and their trait present in both male and female
b) Reciprocal cross results aren’t change
c) Exhibit extensive phenotypic variation
d) Reciprocal cross results are change
e) Mendel’s principle of segregation and independent assortment are follow
TLS Online TPP Program
#Question id: 12703
#Unit 8. Inheritance Biology
In the plants, due to mutation in the mitochondrial genome causing cytoplasmic male sterility can be influenced by the nuclear gene (Rf), which is dominant over the cytoplasmic mitochondrial genome. If a male sterile plant is pollinated by the fertile male plant with homozygous (Rf)condition, the progeny obtained in F1 will have
TLS Online TPP Program
#Question id: 12704
#Unit 8. Inheritance Biology
Cytoplasmic male sterility (CMS) in plants is caused by mutation in the mitochondrial genome. CMS can be restored by a nuclear gene, restorer of fertility (Rf), which is a dominant character.
TLS Online TPP Program
#Question id: 12705
#Unit 8. Inheritance Biology
In Neurospora crasssa, the mutant exhibit poky phenotype, when a female of poky strain is crossed with a normal strain acting as a male , all progeny individuals shows poky phenotype . however, the reciprocal cross resulted in all normal progeny. These results can be explained on the basis of