Choose the correct statement

a.The 30-nm fiber is further folded, results in 10000-fold compaction in euchromatin in interphase chromatin and in mitotic chromosomes to achieve an overall 10,00- fold compaction in euchromatin.

b.This 30-nm fiber is further folded, results in 1000-fold compaction in euchromatin in interphase chromatin and in mitotic chromosomes to achieve an overall 10,000- fold compaction in euchromatin.

c.Heterochromatin generally maintains 10,000-fold compaction in both interphase and mitosis after 30 nm.

d.Heterochromatin generally maintains 10,00-fold compaction in interphase and 10,000 folds in  mitosis after 30 nm.

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#Question id: 828

#Unit 1. Molecules and their Interaction Relevant to Biology

Which of the following assistance have function to lift folding polypeptides out of the false minima in their folding funnels?

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#Question id: 11878

#General Aptitude

The greatest number by which 2300 and 3500 are divided leaving the remainders of 32 and 56 respectively is

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#Question id: 23219

#Unit 13. Methods in Biology

Immunoelectron microscopy is used for localizing proteins in thin sections at the electron microscope level. What is use to make antibody visible?

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#Question id: 17075

#Unit 12. Applied Biology

What are the disadvantages of using polyclonal antibodies?

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#Question id: 14708

#Unit 5. Developmental Biology

Difference between gastrulation in Xenopus and sea urchin;

I. In Xenopus, formation of blastopore: mesoderm and endoderm move inside by involution over blastopore lip.

II. In sea urchin, formation of blastopore: mesodermal cells migrate into the interior; endoderm moves inside by invagination of the epithelial sheet.