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TLS Online TPP Program

#Question id: 2882

SUMO (small ubiquitin-related modifier) proteins are ∼10-kD polypeptides that function as reversible post-translational protein modifiers. They form isopeptide bonds with ɛ-amino groups of acceptor Lys residues in hundreds of target proteins in a process termed as sumoylation. Which of the following statements is correct regarding this modification?

#Unit 2. Cellular Organization

  1. A short non-covalent SUMO-interaction/binding motif (SIM/SBM) has been identified in all SUMO enzymes, targets and downstream effectors. This motif contributes to the mechanism and consequences of sumoylation.

  2. Acceptor Lys residues in target proteins are frequently found in the consensus motif ΨKxD although the number of targets with non-consensus acceptor sites is steadily increasing.

  3. Irreversible sumoylation contributes to many distinct pathways, such as chromatin structure, DNA repair, transcription, cell-cycle progression and trafficking.

  4. Sumoylation alters the molecular interactions of modified target proteins by masking or adding interaction surfaces. Downstream consequences, which are target dependent, include changes in localization, activity and protein stability.

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TLS Online TPP Program

#Question id: 13148

#Unit 8. Inheritance Biology

During  a three point test cross is carried out. The parental cross was  AABBCC  X  aabbcc , the F1 progeny is AaBbCc. What will be the no. of given genotype in 100 progeny?
i) AaBbCc               ii) aaBbcc
TLS Online TPP Program

#Question id: 13149

#Unit 8. Inheritance Biology

A three point test cross was made between the  st^+-e^+-ss^+  and  st-e-ss , the genotype of the double cross over  will be;  st^+-e-ss^+  and st-e^+-ss. Based on this, determine the order of the genes.
TLS Online TPP Program

#Question id: 13150

#Unit 8. Inheritance Biology

A fruit fly Drosophila melanogaster showing  three point test cross  st+-e+-ss+  was crossed with triplet recessive mutant st-e-ss. The F1 hybrid  was the backcross with the recessive mutant and the phenotype recorded as follows;

The distance in map unit (mu) between  st+  to  e+ and e+ to ss+ is
TLS Online TPP Program

#Question id: 13151

#Unit 8. Inheritance Biology

A series of two-point crosses were carried out among five loci (a, b, c, d and e) producing the following recombination frequencies. Using these recombination frequencies, map these five loci, showing  their linkage groups, the order of the loci in each linkage group is;

What is the correct order of the loci?
TLS Online TPP Program

#Question id: 13153

#General Aptitude

The in-radius of an equilateral triangle is of length 3 cm. Then the length of each of its medians is
TLS Online TPP Program

#Question id: 13154

#Unit 2. Cellular Organization

In starving cells, however, such degradation would deplete essential enzymes and regulatory proteins. Lysosomes therefore also have a selective pathway, which is activated only after a prolonged fast, that imports and degrades cytosolic proteins containing the pentapeptide  , the sequence is