Expression of a cloned eukaryotic gene in a bacterial cell involves many challenges. The use of mRNA and reverse transcriptase is part of a strategy to solve the problem of

TLS Online TPP Program

#Question id: 12695

#Unit 8. Inheritance Biology

A panel of cell lines was created by human—mouse somatic-cell hybridization. Each cell line was examined for the presence of human chromosomes and for the production of three enzymes. The following results were obtained: 

On the basis of these results, give the chromosomal locations of the genes encoding enzyme 1, enzyme 2, and enzyme 3. 

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#Question id: 12696

#Unit 8. Inheritance Biology

The following is a schematic representation of region of the chromosome of fly along with extent of six deletions (Del 1 to Del 6); 

When flies homozygous for the recessive mutations are crossed with flies heterozygous for the deletions, the following results are obtained, in which "m" represents a mutant phenotype and a plus sign (+) represents the wild type. On the basis of these data, determine the relative order of the seven mutant eenes on the chromosome. 

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#Question id: 12697

#Unit 7. System Physiology – Animal

The following test results were obtained: urine flow rate = 2.0 ml/min; urine inulin concentration = 60 mg/ml; plasma inulin concentration = 2 mg/ml; urine potassium concentration = 20 μmol/ml; plasma potassium concentration = 4.0 μmol/ml; urine osmolarity = 150 mOsm/L; and plasma osmolarity = 300 mOsm/L. What is the approximate GFR?

TLS Online TPP Program

#Question id: 12698

#Unit 7. System Physiology – Animal

The following test results were obtained: urine flow rate = 2.0 ml/min; urine inulin concentration = 60 mg/ml; plasma inulin concentration = 2 mg/ml; urine potassium concentration = 20 μmol/ml; plasma potassium concentration = 4.0 μmol/ml; urine osmolarity = 150 mOsm/L; and plasma osmolarity = 300 mOsm/L. What is the net potassium reabsorption rate?

TLS Online TPP Program

#Question id: 12699

#Unit 7. System Physiology – Animal

The following test results were obtained: urine flow rate = 2.0 ml/min; urine inulin concentration = 60 mg/ml; plasma inulin concentration = 2 mg/ml; urine potassium concentration = 20 μmol/ml; plasma potassium concentration = 4.0 μmol/ml; urine osmolarity = 150 mOsm/L; and plasma osmolarity = 300 mOsm/L. What is the free water clearance rate?

TLS Online TPP Program

#Question id: 12700

#Unit 7. System Physiology – Animal

A young man is found comatose, having taking an unknown number of sleeping pills an unknown time before. An arterial blood sample yields the following values: pH = 7.02, HCO3− = 14 mEq/L, and PCO2 = 68 mm Hg. This patient’s acid–base status is most accurately described as