In Neurospora, the mutant stp exhibits erratic stop-and start growth. When a female of stp strain is crossed with a normal strain acting as a male, all progeny individuals' showed stp mutant phenotype. However, the reciprocal cross resulted in all normal progeny, individuals. These results can be explained on the basis of

A. Uniparental gene contribution

B. Nuclear inheritance with concept of dominance

C. Sex link character

D. stp mutation may be located in chloroplast DNA

The most appropriate statement or combination of the above statements for explaining the experimental results is:

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#Question id: 12499

#Unit 8. Inheritance Biology

On the basis of the linked marker genotypes II 3 can be told that:

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#Question id: 12500

#Unit 8. Inheritance Biology

In this pedigree II 1 is affected with an autosomal recessive disorder. The disease status for II 2, II 3 and II 4 is unknown. A and B represent alleles at a locus which is tightly linked to the disease locus with recombination fraction of 0. On the basis of the linked markers II 2 can be told that: 

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#Question id: 12501

#Unit 8. Inheritance Biology

In the pedigree shown, on the basis of the linked marker results II 3 can be told that:

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#Question id: 12502

#Unit 8. Inheritance Biology

In the pedigree shown, on the basis of the linked marker results II 4 can be told that:

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#Question id: 12503

#Unit 8. Inheritance Biology

In this pedigree II 1 is affected with an autosomal recessive disorder. The disease status for II 2 is unknown. A and B represent alleles at a locus which is tightly linked to the disease locus with recombination fraction of 0. Using the linked markers, II2 can be told that:

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#Question id: 12504

#Unit 8. Inheritance Biology

In this pedigree II 3 and III 1 are affected with an X-linked recessive disorder which is tightly linked to a marker locus with alleles A and B, with a recombination fraction of 0 between the disease and marker loci. Analysis of the linked marker results indicates that the disease must be segregating with: