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#Question id: 10140


Following are certain statements regarding activated and inactivated form of Rubisco, Which one is INCORRECT?

#Unit 6. System Physiology – Plant
  1. The naturally occurring inhibitor 2-carboxyarabinitol 1-phosphate prevent activation of Rubisco
  2. plant rubisco active site contains His, Asp, Glu and Lys 201 , is a carbamoylated Lys 201 side chain with a bound Mg 2+ ion and is absoluetly require for its activation
  3. The increase in both pH and concentration of Mg2+ facilitates the formation of the (E–NH 3 + – CO2 – • Mg2+) complex, which represents the catalytically active form of rubisco
  4. The tight binding of sugar phosphates, such as ribulose 1,5-bisphosphate (RuBP), either impedes the production of the E–carbamate adduct or blocks the binding of substrates to the carbamylated enzyme
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TLS Online TPP Program

#Question id: 5733

#Unit 8. Inheritance Biology

In individuals heterozygous for a chromosome inversion, the homologous chromosomes form a loop in prophase I of meiosis.

Which of the following is effect of inversion?

A. A dicentric and an acentric chromosome in meiosis I as the chiasmata gets terminated when inversion includes centromere  

B. Appearance of deletion and duplication in both the cross over products chromosomes when centromere outside of inversion region  

C. All recombinant gamete are non-viable gametes when single crossing over within inverted region; irrespective to paracentric or pericentic inversion

D. Nonviable gametes are usually produced, resulting in a depression in observed recombination frequencies.

Which of the above statements are correct?

TLS Online TPP Program

#Question id: 5734

#Unit 8. Inheritance Biology

Following is heterozygote for inversion?

Following some statement given for above abnormality?

A) There is a less probability of a crossover occurring within inversion region and producing an enviable cross over meiotic product.

B) Chromosomes that have engaged in crossing-over separate in the normal fashion, without the creation of a bridge

C) The crossover produces chromatids that contain duplication and a deletion for different parts of the chromosome results non viable gamete

D) Double cross over within inversion loop will be results all viable gamete of parental and recombinant

TLS Online TPP Program

#Question id: 5735

#Unit 8. Inheritance Biology

Aneuploids may arise through nondisjunction, the failure of homologous chromosomes or sister chromatids to separate in meiosis. Following some statement are correct.

A)  Meiosis I non-disjunction leads to produce all gamete become aneuploidy

B) Meiosis II non-disjunction leads to produce half of gametes n+1 other half normal haploid

C) Meiosis I non-disjunction leads to produce half of gametes n+1 other half n-1

D) Either meiosis I or meiosis II non-disjunction leads to produce all aneuploidy gamete

TLS Online TPP Program

#Question id: 5736

#Unit 8. Inheritance Biology

Two zygote in which one A is 44+XYY and another B is 44+XXX karyotype is best described by

TLS Online TPP Program

#Question id: 5737

#Unit 8. Inheritance Biology

When an organism gains one extra copy of a chromosome but not a complete haploid set, the conditions is known as

TLS Online TPP Program

#Question id: 5738

#Unit 8. Inheritance Biology

It was once thought that the ____ karyotype was related to criminal disposition because it led to aggressive behavior due to excessive "maleness".