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#Question id: 802


A single-stranded DNA molecule contains 40 nucleotides with equal amounts of A, C, G, and T. This DNA strand can combine with a complementary DNA strand to form a double-stranded DNA molecule. Which is a possible sequence and structure for this DNA molecule?

#Unit 1. Molecules and their Interaction Relevant to Biology
  1. If the single-stranded molecule has the sequence 5’-(ATGC)10, then its double- stranded form could assume a Z-DNA structure.

  2. If the single-stranded molecule has the sequence 5’-(GATC)10, then its double-stranded form could assume an H-DNA structure.

  3. If the single-stranded molecule has the sequence 5’-(CTGA)10, then its double-stranded form could assume a hairpin structure.

  4. If the single-stranded molecule has the sequence 5’-(TGAC)10, then its double-stranded form could assume a cruciform structure.

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#Question id: 7518

#General Aptitude

In a flight of 800 km, an aircraft was slowed down due to bad weather. Its average speed for the trip was reduced by 200 km/h and the time of flight increased by 20 min. The duration of the flight is

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#Question id: 5775

#Unit 8. Inheritance Biology

A point mutation that changes a codon specifying an amino acid into a stop codon is called a

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#Question id: 10432

#Unit 6. System Physiology – Plant

Phytochrome interacting factors (PIFs) act as negative regulators of photomorphogenesis such as;
a) Most PIFs are constitutive activators of genes that are expressed in the dark or in response to shade
b) Most PIFs are constitutive repressor of genes that are expressed in the dark or in response to shade
c) In the light, Pfr promotes the degradation of the PIFs, blocking the transcription of skotomorphogenesis genes
d) In the light, Pfr promotes the activation of the PIFs, blocking the transcription of skotomorphogenesis genes
Which of the following combinations is correct about PIFs?

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#Question id: 13089

#Unit 13. Methods in Biology

To express a yeast gene in E. coli, your task is to design a strategy to insert the yeast gene into the bacterial plasmid. Below is a map of the area of the yeast genome surrounding the gene in which you are interested.

 
The distance between each tick mark placed on the line above is 100 bases in length
Below are the enzymes you can use, with their specific cut sites shown 5’-XXXXXX-3’ 3’-XXXXXX-5’

 
The plasmid is 5,000 bases long and the two farthest restriction enzyme sites are 200 bases apart. The plasmid has an ampicillin resistance gene somewhere on the plasmid distal from the restriction cut sites.
                              
You do the digestion of the insert and the vector and then ligate the two digestions together. You then transform the ligation into bacteria and select for ampicillin resistance. You get three colonies on your transformation plate. You isolate plasmid from each one and cut each plasmid with the enzyme XbaI. You then run your three digestions on an agarose gel and see the following patterns of bands. Describe what each plasmid actually was that was contained in each of the three colonies.
 
What is the Colony 2’s plasmid is;

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#Question id: 13219

#Unit 6. System Physiology – Plant

In the apoplast pathway, water moves exclusively