Given some statements about the roles of phytochrome and gibberellin in shade avoidance response;

A) In direct sunlight, red light predominates and the Pfr form of phytochrome moves into the nucleus.

B) Under a plant canopy, the light is enriched in far-red wavelengths. Phytochrome is in the inactive Pr form.

C) As PIF proteins accumulate, PIF-induced gene expression increases, promoting stem elongation.

D) Phy causes the turnover of PIF proteins, which act as negative regulators of  photomorphogenesis

E) In the absence of Pfr, PIFs are not degraded, the sensitivity to gibberellin increases, causing the degradation of DELLA repressors

F) As a result, DELLA repressors bind PIF and prevent the transcription of PIF-regulated gene, In the absence of PIF-induced gene expression, stem growth is limited.

Find out the correct sequence of these responses.

TLS Online TPP Program

#Question id: 34108

#Unit 2. Cellular Organization

What is order of steps to visualise Individual bands containing particular genes can be identified by in situ hybridization.

A. Target cells squashed on slide and freeze in dry ice

B. Wash with ethanol

C. Dip in agar solution

D. Denature DNA

E. Add radioactive probe

F. Wash off unreacted probe

G. Autoradiography

TLS Online TPP Program

#Question id: 34109

#Unit 2. Cellular Organization

A. The chromocenter of polytene chromosome consists largely of heterochromatin

B. The chromocenter of polytene chromosome that consists largely of euchromatin

C. Chromocenter is all four chromosomes of D. melanogaster aggregate

D. Polytene chromosome are formed by a process known as endoreduplication

Which combination of statement is correct

TLS Online TPP Program

#Question id: 34110

#Unit 2. Cellular Organization

A. DNA is wrapped 1.67 times around the histone octamer.

B. The structure of the DNA is altered so that it has an increased number of base pairs/turn in the middle, but a decreased number at the ends.

C. 0.6 negative turns of DNA are absorbed by the change in bp/turn from 10.5 in solution 

D. 10.2 bp/turn on the nucleosomal surface is linking-number paradox.

Find true and false

TLS Online TPP Program

#Question id: 34111

#Unit 2. Cellular Organization

A. 11-nm chromatin fibers consist of a string of nucleosomes.

B. 30-nm fibers have six nucleosomes/turn, which are organized into a two-start helix.

C. Histone H1, histone tails, and increased ionic strength all promote the formation of the 11-nm fiber.

D. Histone octamers are well conserved during replication, with H2A-H2B dimers and H32-H42 tetramers are.

Which of the correct combination of statements

TLS Online TPP Program

#Question id: 34112

#Unit 2. Cellular Organization

A. When interphase nuclei are suspended in a solution of low ionic strength, they swell and rupture to release fibers of chromatin.

B. Individual nucleosomes can be obtained by treating chromatin with the endonuclease micrococcal nuclease

C. When chromatin is digested with MNase, the DNA is cleaved into integral multiples of a unit length can be Fractionated by gel electrophoresis reveals the “ladder”

D. With MNase more than 95% of nuclear DNA can be recovered in the form of the 200-bp ladder.

Choose true and false

TLS Online TPP Program

#Question id: 34113

#Unit 2. Cellular Organization

Which of the following is incorrect statement