In Arabidopsis mutant overexpressing the YUCCA6 gene causes

TLS Online TPP Program

#Question id: 29109

#Unit 8. Inheritance Biology

If the probability of being blood types are;

Blood type A = 1/4

Blood type B = 3/4

Blood type O = 1/2

what is the probability of being either blood-type A  or blood-type B ?

TLS Online TPP Program

#Question id: 29110

#Unit 8. Inheritance Biology

When two parents heterozygous for albinism mate (Aa X Aa), the probability

of their having a child with albinism (aa) is 1/4 and the probability of having a child with normal pigmentation (AA or Aa) is 3/4 . What is the probability of this couple having 5 children, two with albinism and three with normal pigmentation?

TLS Online TPP Program

#Question id: 29111

#Unit 8. Inheritance Biology

A plant with purple flowers is crossed with a plant with white flowers, and the F1 are self-fertilized to produce 105 F2 progeny with purple flowers and 45 with white flowers.

A scientist hypothesized that there are two genes with identical functions that control the dominant trait. The scientist also proposed that the two genes are not linked. The scientist carried out a chi-square test to test the hypothesis. Which one of the following options is the correct chi-square value obtained by the scientist?

TLS Online TPP Program

#Question id: 29112

#Unit 8. Inheritance Biology

An example of multiple alleles is at a locus that determines the feather pattern of mallard ducks. One allele, M, produces the wild-type mallard pattern, MR, produces restricted, and a third allele, md, produces dusky. In this allelic series, dominancy shows MR >M > md

If a cross between  MR md X M md, What proportion of progeny will be restricted?

TLS Online TPP Program

#Question id: 29114

#Unit 8. Inheritance Biology

Given below, is the result of a complementation test for six independent mutants (1 to 6)

TLS Online TPP Program

#Question id: 29115

#Unit 8. Inheritance Biology

Given below, is the result of a complementation test for seven independent mutants (A to G). '+' represents complementation; '_' represents non complementation. Based on the above, which one of the following conclusions is correct

a) The mutations can be ordered in a three cistron as A-G-B-C-D-E-F

b) All mutations belong to a single cistron, but their order cannot be determined.

c) There are three cistrons, mutations A and G represent one cistron, B, C and D represent the second cistron and E and F represents the third cistron.

d) There are three linkage groups, mutations A and G  represent linkage group-I, B, C and D represent linkage group-II, and E and F represents linkage group-III