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#Question id: 12991


Choose the correct statements
a. Secondary structures are stabilized by hydrogen bonds.
b. Hydrogen bond always formed between non bonded atoms.
c. the folded length of an amino acid in α-helix reduced almost 3 times than linear structure.
d. Only dihedral angle changes during the formation of secondary structure while bond length remains unchanged

#Unit 1. Molecules and their Interaction Relevant to Biology
  1. a and b only
  2. a, c, and d 
  3. a, b, and c 
  4. a, b, c, d 
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TLS Online TPP Program

#Question id: 4097

#Unit 3. Fundamental Processes

The 3' end of most eukaryotic mRNAs is defined by the addition of a polyA tail - a processing reaction called polyadenylation. Choose correct set of proteins involved in the polyadenylation

TLS Online TPP Program

#Question id: 4098

#Unit 3. Fundamental Processes

A merodiploid with a mutant repressor gene (Is) is shown below. The mutant repressor therefore binds irreversibly to both operators and will render

TLS Online TPP Program

#Question id: 4099

#Unit 3. Fundamental Processes

Five E. coli strains have been identified, each of which has a different mutation that disrupts the normal regulation of a particular operon. For each mutant strain, the mutation has been mapped to the promoter or the operator region; however, the exact sequence changes are not known for these mutations. It is known that the normal promoter/operator consists of a single binding site for a positively acting transcription factor located just upstream of the promoter itself. Short DNA fragments containing the promoter and the operator were subcloned from each of the five mutant strains and from the wild type, purified, and radiolabeled. These fragments were then incubated under conditions of DNA excess with either purified regulatory factor or RNA polymerase or with both polymerase and regulatory factor.

The resulting protein-DNA complexes were separated by electrophoresis, and the radioactive DNA fragments were detected by exposure to x-ray film, giving the results shown below. Electrophoresis is from top to bottom; the largest complexes run slowest.

Based on above experiment, match the following

Effect

Mutant

1. One of the mutations increases the affinity of the polymerase for the promoter. Transcription of the operon is not stimulated by the regulatory factor in this mutant.

A. Mutant 5

2. One of the mutations maps to the operator.

Transcription of the operon is not stimulated by the regulatory factor in this mutant. Which mutant is most likely to show this effect

B. Mutant 2

3. One of the mutations is known to result from a small deletion between the operator and the promoter. The polymerase and the regulatory factor is each able to bind to the mutated DNA sequence, but are unable to form the three components complex. Transcription of the operon is not stimulated by the regulatory factor in this mutant. Which mutant shows the properties that might be expected for such a change?

C. Mutant 4

D. Mutant 3

E. Mutant 1

TLS Online TPP Program

#Question id: 4100

#Unit 3. Fundamental Processes

some pre-mRNAs are spliced by an alternative, low-abundance form of the spliceosome. This rare form contains some components common to the major spliceosome, but it contains other unique components such as

TLS Online TPP Program

#Question id: 4101

#Unit 3. Fundamental Processes

In order to ensure that only fully processed mature mRNAs are allowed to be exported to cytosol, pre-mRNAs associated with snRNPs are retained in the nucleus. To demonstrate this, an experiment was performed where a gene coding a pre-mRNA with a single intron was mutated either at the 5’ or 3’ splice sites or both the splice sites.

Given below are a few possible outcomes, Choose NOT FEASIBLE OUTCOME

A. Pre-mRNA having mutation at both the splice sites will be retained in the nucleus because of the presence of bound snRNPs.

B. Pre-mRNA having mutation at both the splice sites will be exported to cytosol because of the absence of bound snRNPs.

C. Pre-mRNA mutated at either 3’ or 5’ splice sites will be retained in the nucleus because of the presence of bound snRNPs.

D. Pre-mRNA mutated at either 3’ or 5’ splice sites will be exported to cytosol because of the absence of bound snRNPs.

TLS Online TPP Program

#Question id: 4102

#Unit 3. Fundamental Processes

Given the following monoploid operons, which would not synthesize lactose permease under any circumstance?