TLS Online TPP Program

#Question id: 352


One mole (mol) of glucose (molecular mass = 180 daltons) is ________.

#Part-A Aptitude & General Biotechnology
  1. 180 × 1023 molecules of glucose

  2. 1 kilogram of glucose dissolved in 1 liter of solution

  3. 180 mL of dissolved glucose

  4. 180 grams of glucose

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TLS Online TPP Program

#Question id: 11281

#Part-B Specialized Branches in Biotechnology

Owls eat rats, mice, shrews, and small birds. Assume that, over a period of time, an owl consumes 5,000 J of animal material. The owl loses 2,300 J in feces and owl pellets and uses 2,500 J for cellular respiration. What is the production efficiency of this owl?

TLS Online TPP Program

#Question id: 11281

#Part-B Specialized Branches in Biotechnology

Owls eat rats, mice, shrews, and small birds. Assume that, over a period of time, an owl consumes 5,000 J of animal material. The owl loses 2,300 J in feces and owl pellets and uses 2,500 J for cellular respiration. What is the production efficiency of this owl?

TLS Online TPP Program

#Question id: 11282

#Part-B Specialized Branches in Biotechnology

Which of the following ecosystems would likely have the largest net primary productivity per hectare and why?

TLS Online TPP Program

#Question id: 11282

#Part-B Specialized Branches in Biotechnology

Which of the following ecosystems would likely have the largest net primary productivity per hectare and why?

TLS Online TPP Program

#Question id: 11283

#Part-B Specialized Branches in Biotechnology

Herbivore ingests plant material with 1000 k j energy form producer and assimilated only 200 k J energy in their blood stream; additionally herbivore invests 120 k j energy in their maintenance. What is production efficiency of that herbivore?

TLS Online TPP Program

#Question id: 11284

#Part-B Specialized Branches in Biotechnology

Which of the following could qualify as a top-down control on a grassland community?