TLS Online TPP Program

#Question id: 3267


In a typical Mendelian population, individuals carrying gene ‘a’ in homozygous condition suffer from phenylketonurea. Those with A in homozygous condition are normal. Others, who are heterozygotic with Aa, are carriers. If the frequency of ‘a’ in a population is 0.20, what is the percentage of normal individual in the population?

#Part-A Aptitude & General Biotechnology
  1. 64     

  2. 32         

  3. 96

  4. 90

More Questions
TLS Online TPP Program

#Question id: 5730

#Part-B Specialized Branches in Biotechnology

In a family, father is homozygous dominant (AA) for a gene A and his wife is homozygous for its ressive allele (aa) showing albino phenotype. It was surprising that their child showed the albino phenotype. Which of the following phenomenon can explain the phenotype?

TLS Online TPP Program

#Question id: 5732

#Part-B Specialized Branches in Biotechnology

Consider a plant, such as maize, heterozygous for a paracentric inversion. The inversion is very small and a synapsed inversion loop does not occur in any of the cells. Which of the following statement is correct?

TLS Online TPP Program

#Question id: 5733

#Part-B Specialized Branches in Biotechnology

In individuals heterozygous for a chromosome inversion, the homologous chromosomes form a loop in prophase I of meiosis.

Which of the following is effect of inversion?

A. A dicentric and an acentric chromosome in meiosis I as the chiasmata gets terminated when inversion includes centromere  

B. Appearance of deletion and duplication in both the cross over products chromosomes when centromere outside of inversion region  

C. All recombinant gamete are non-viable gametes when single crossing over within inverted region; irrespective to paracentric or pericentic inversion

D. Nonviable gametes are usually produced, resulting in a depression in observed recombination frequencies.

Which of the above statements are correct?

TLS Online TPP Program

#Question id: 5735

#Part-B Specialized Branches in Biotechnology

Aneuploids may arise through nondisjunction, the failure of homologous chromosomes or sister chromatids to separate in meiosis. Following some statement are correct.

A)  Meiosis I non-disjunction leads to produce all gamete become aneuploidy

B) Meiosis II non-disjunction leads to produce half of gametes n+1 other half normal haploid

C) Meiosis I non-disjunction leads to produce half of gametes n+1 other half n-1

D) Either meiosis I or meiosis II non-disjunction leads to produce all aneuploidy gamete

TLS Online TPP Program

#Question id: 5736

#Part-B Specialized Branches in Biotechnology

Two zygote in which one A is 44+XYY and another B is 44+XXX karyotype is best described by

TLS Online TPP Program

#Question id: 5737

#Part-A Aptitude & General Biotechnology

When an organism gains one extra copy of a chromosome but not a complete haploid set, the conditions is known as