TLS Online TPP Program

#Question id: 12915


Which of the following statement is not correct about PCR.

#Part-A Aptitude & General Biotechnology
  1. It provides rapid means for DNA identification and analysis.
  2. It helps in the investigation of cellular and molecular processes.
  3. It is used to amplify a precise fragment of DNA.
  4. It does not require the knowledge of DNA sequence.

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TLS Online TPP Program

#Question id: 5428

#Part-A Aptitude & General Biotechnology

If trait are governed by polygenic. If plant genotype AABB  ( 8 cm height ) were cross with aabb ( 2 cm height ) produced F1 and allowed to selfing . which of the following phenotypic height are not observe in F2 plant if all gamete participate in fertilization ?

TLS Online TPP Program

#Question id: 4129

#Part-A Aptitude & General Biotechnology

Which of the following statements about the tRNA that normally accepts phenylalanine is false?  (mRNA codons for phenylalanine are UUU and UUC.)

TLS Online TPP Program

#Question id: 18666

#Part-A Aptitude & General Biotechnology

The above figure shows where sample applied was 100 µg of total protein extracted from a normal dog heart ventricle. The first dimension was conducted using a pH 4–7 isoelectric focussing gel. The second dimension was a 12% SDS–PAGE vertical slab gel. The pattern was visualised by silver staining. Which of the following techniques is applied

TLS Online TPP Program

#Question id: 19700

#Part-B Specialized Branches in Biotechnology

Different leads are used to record ECG of humans, these leads can be either bipolar or unipolar. Which one of the following is NOT unipolar leads?

TLS Online TPP Program

#Question id: 14254

#Part-B Specialized Branches in Biotechnology

Hybridoma cells immobilized on surfaces of Sephadex beads are used in a packed column for production of monoclonoal antibodies (Mab). Hybridoma concentration is approximately X = 5 g/l in the bed. The flow rate of the synthetic medium and glucose concentration are Q = 2 l/h and S0 = 40 g/l, respectively. The rate constant for Mab formation is k = 1 gX/l-d. Assume that there are no diffusion limitations and glucose is the rate limiting nutrient.  Determine the height of the packed bed for 95% glucose conversion. Bed diameter is D0 = 0.2 m. Neglect the growth of the hybridomas and assume first order kinetics.