The reason for TBP’s unorthodox recognition mechanism is

TLS Online TPP Program

#Question id: 19486

#Part-B Specialized Branches in Biotechnology

The growth of S.cerevisiae on glucose under anaerobic conditions can be described by the following reaction:

C₆H₁₂O₆ + aNH₃ → 0.59 CH_1.64N_0.16O_0.52 (biomass) + 0.43 C₃H₈O₃ + 1.54CO₂ + 1.3C₂H₅OH + 0.036H₂O 

and determine the product yield coefficient Y etoh/s and determine coefficient a.

TLS Online TPP Program

#Question id: 19488

#Part-B Specialized Branches in Biotechnology

What is the yield coefficient if the initial substrate concentration is 10 g/l and biomass is 0.1 g/l. The substrate is then consumed and produces 5.3 g/l of biomass?

TLS Online TPP Program

#Question id: 19531

#Part-B Specialized Branches in Biotechnology

According to the Balances on steady-state processes, the accumulation is equal to?

TLS Online TPP Program

#Question id: 19534

#Part-B Specialized Branches in Biotechnology

The equation of material balance, (Final condition + Sum of outputs) is equal to which of the following?

TLS Online TPP Program

#Question id: 19535

#Part-B Specialized Branches in Biotechnology

A container has 10 grams of water 5 grams of water is added and 2 grams of water is taken out, what is the final amount of water?

TLS Online TPP Program

#Question id: 19537

#Part-B Specialized Branches in Biotechnology

The equation for aerobic production of acetic acid from ethanol is ____________

C2H5OH(ethanol) + O2(acetic acid) → CH3CO2H + H2O

Acetobacter aceti bacteria are added to vigorously-aerated medium containing 10 g l^-1 ethanol. After some time, the ethanol concentration is 2 g l^-1 and 7.5 g l^-1 acetic acid is produced. Calculate the Observed yield.