Stoichiometric equations are used to represent growth of microorganisms provided a ' molecular formula' for the cells is available. The molecular formula for biomass is obtained by measuring the amounts of C, N, H, O and other elements in cells. For a particular bacterial strain, the molecular formula was determined to be C4.4H7.30 1.2N0.86 . These bacteria are grown under aerobic conditions with hexadecane (C16H34) as substrate. The reaction equation describing growth is:

                             

You have been put in charge of a small fermenter for growing the bacteria and aim to produce 2.5 kg of cells for inoculation of a pilot-scale reactor. What minimum amount of hexadecane substrate must be contained in your culture medium? 

TLS Online TPP Program

#Question id: 14392

#Section 1: Engineering Mathematics

 If  , then the value of x is 

TLS Online TPP Program

#Question id: 14393

#Section 1: Engineering Mathematics

If the system of equations 2x + 3y + 5 = 0, x + ky + 5 = 0, kx — 12y — 14 = 0 has non-trivial solution, then the value of k is 

TLS Online TPP Program

#Question id: 14394

#Section 5: Bioprocess Engineering and Process Biotechnology

1.0 timol of an enzyme that contains five active sites per molecule converts 1.0 pmol substrate every 2 microseconds. Calculate catalytic centre activity (sec^-1). ......10^5

TLS Online TPP Program

#Question id: 14395

#Section 5: Bioprocess Engineering and Process Biotechnology

An enzyme is available at a specific activity of 500 units/mg protein. For an assay, 10miro mole substrate need to be converted per minute. What mass (in mg) of protein would you take for this to be achieved? 

TLS Online TPP Program

#Question id: 14396

#Section 5: Bioprocess Engineering and Process Biotechnology

A purified hydrolytic enzyme (Mr 150 000) is available with the description: Gives a Vmax of 3 200 units/mg protein under optimal conditions. How many micromoles of substrate can be hydrolysed by 1 mg of protein in 1 minute  

TLS Online TPP Program

#Question id: 14397

#Section 5: Bioprocess Engineering and Process Biotechnology

A purified hydrolytic enzyme (Mr 150 000) is available with the description: Gives a Vmax of 3 200 units/mg protein under optimal conditions. How many nmol of enzyme are there in 1 mg