TLS Online TPP Program

#Question id: 3559


Homozygous yellow was crossed with green seed plant. All F1 offspring having yellow seed plant were allowed to self fertilization to produced F2 plant. Further F2 plant self fertilized. What is phenotype ratio in F3 generation?

#Section 3: Genetics, Cellular and Molecular Biology
  1. 3: 1              

  2. 5:3                  

  3. 5:6              

  4. 6:1

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TLS Online TPP Program

#Question id: 14260

#Section 5: Bioprocess Engineering and Process Biotechnology

C. roseus cells immobilized in Ca-alginate beads of diameter 0.5 mm are used for production of indole alkaloids (IA) in a fluidized-bed bioreactor. The rate limiting nutrient is glucose and no intraparticle diffusion limitations exist. Use the following data: Flow rate of the feed: Q = 1 l/h, Glucose in the feed: So = 30 g/l, Plant Cell Concentration: X = 6 g/l reac. The rate constant for IA formation: k = 5 d-1 (g/l)^-1 Ks = 0.4 g/l, Column diameter: Do = 0.15 m. Growth is negligible and Monod kinetics is valid. For 95% glucose conversion determine height of the column 

TLS Online TPP Program

#Question id: 14261

#Section 5: Bioprocess Engineering and Process Biotechnology

C. roseus cells immobilized in Ca-alginate beads of diameter 0.5 mm are used for production of indole alkaloids (IA) in a fluidized-bed bioreactor. The rate limiting nutrient is glucose and no intraparticle diffusion limitations exist. Use the following data: Flow rate of the feed: Q = 1 l/h, Glucose in the feed: So = 30 g/l, Plant Cell Concentration: X = 6 g/l reac. The rate constant for IA formation: k = 5 d-1 (g/l)^-1 Ks = 0.4 g/l, Column diameter: Do = 0.15 m. Growth is negligible and Monod kinetics is valid. If Yp/s is 0.02 g IA/g glu, determine IA concentration in the effluent.
_______________

TLS Online TPP Program

#Question id: 14262

#Section 5: Bioprocess Engineering and Process Biotechnology

The BOD5 value of a waste-water feed stream to an activated-sludge unit is S0 = 300 mg/l, and the effluent is desired to be S = 30 mg/l. The feed flow rate is F = 2× 10^7 l/day. For the recycle ratio of α = 0.5 and a steady-state biomass concentration of X = 5 g/l, Use the following kinetic parameters:

 
calculate Required reactor volume (V). 
_______________10^6

TLS Online TPP Program

#Question id: 14263

#Section 5: Bioprocess Engineering and Process Biotechnology

The BOD5 value of a waste-water feed stream to an activated-sludge unit is S0 = 300 mg/l, and the effluent is desired to be S = 30 mg/l. The feed flow rate is F = 2× 10^7 l/day. For the recycle ratio of α = 0.5 and a steady-state biomass concentration of X = 5 g/l, Use the following kinetic parameters:

 
calculate Biomass concentration in recycle (Xr).

TLS Online TPP Program

#Question id: 14264

#Section 5: Bioprocess Engineering and Process Biotechnology

The BOD5 value of a waste-water feed stream to an activated-sludge unit is S0 = 300 mg/l, and the effluent is desired to be S = 30 mg/l. The feed flow rate is F = 2× 10^7 l/day. For the recycle ratio of α = 0.5 and a steady-state biomass concentration of X = 5 g/l, Use the following kinetic parameters:

 
calculate Hydraulic residence time
______________

TLS Online TPP Program

#Question id: 14265

#Section 5: Bioprocess Engineering and Process Biotechnology

For the activated-sludge, the specific growth rate of cells is given by 


 

The following parameter values are known: F = 500 l/h, α = 0.4, ɣ = 0.1, Xe = 0, V = 1500 l, Ks = 10 mg/l, µm = 1 h-1 , kd = 0.05 h-1 , S0 = 1000 mg/l, Y M X/S = 0.5 g dw/g substrate. Calculate the substrate concentration (S) in the reactor at steady state. -------------------------