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TLS Online TPP Program
#Question id: 15551
#Section 1: Engineering Mathematics
Compute the root of function f(x) = x2 - 3 after two iterations using bisection method in the interval [0, 2]
TLS Online TPP Program
#Question id: 15552
#Section 1: Engineering Mathematics
One real root of a polynomial P(x) = x3 - x -1 lies in the interval [1,2] and bisection method is used to find its value, the minimum number of iterations required to achieve accuracy up to two decimal points is
TLS Online TPP Program
#Question id: 15553
#Section 1: Engineering Mathematics
A function is defined as f(x) = x2 - 3. Between the interval [1,2] find the root of the function by Bisection Method.
TLS Online TPP Program
#Question id: 15554
#Section 1: Engineering Mathematics
Only one of the real roots of f(x) = x6 - x - 1 lies in the interval 1 s x s 2 and bisection method is used to find its value. For achieving an accuracy of 0.001, the required minimum number of iterations is
TLS Online TPP Program
#Question id: 15555
#Section 1: Engineering Mathematics
If
0, then its roots are . . . .
TLS Online TPP Program
#Question id: 15556
#Section 1: Engineering Mathematics
The value of the determinant