TLS Online TPP Program

#Question id: 1969


A bacterium has elements on its surface that are resistant to lysozyme. If an individual is infected with this bacterium, what is a probable consequence?

#Section 2: General Biology
  1. destruction of the bacterium by NK cells

  2. successful reproduction of the bacterium and continued disease

  3. removal of the bacterium by dendritic cells

  4. the individualʹs humoral immunity will immediately take over

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TLS Online TPP Program

#Question id: 14927

#Section 5: Bioprocess Engineering and Process Biotechnology

Calculate RQ value based on the analysis of the inlet air and the exhaust gas as follows. —Inlet Air: 02, 20.90%; CO2, 0.01% — Outlet Gas: 02, 18.30%; CO2, 2.90% 

TLS Online TPP Program

#Question id: 14928

#Section 5: Bioprocess Engineering and Process Biotechnology

 Escherichia coli grows with a doubling time of 0.5 h in the exponential growth phase. What is the value of the specific growth rate? 

TLS Online TPP Program

#Question id: 14929

#Section 5: Bioprocess Engineering and Process Biotechnology

Escherichia coli grows with a doubling time of 0.5 h in the exponential growth phase. How much time would be required to grow the cell culture from 0.1 to 10 kgdry cell m-3 

TLS Online TPP Program

#Question id: 14930

#Section 5: Bioprocess Engineering and Process Biotechnology

E. coli grows from 0.10 to 0.50 kg dry cell m-3 in 1 h. Assuming exponential growth during this period, evaluate the specific growth rate 

TLS Online TPP Program

#Question id: 14931

#Section 5: Bioprocess Engineering and Process Biotechnology

E. coli grows from 0.10 to 0.50 kg dry cell m-3 in 1 h. Evaluate the doubling time during the exponential growth phase 

TLS Online TPP Program

#Question id: 14932

#Section 5: Bioprocess Engineering and Process Biotechnology

 E. coli grows from 0.10 to 0.50 kg dry cell m-3 in 1 h. How much time would be required to grow from 0.10 to 1.0 kg dry cell m-3? You may assume exponential growth during this period