Find the probability of drawing one rupee coin from a purse with two compartments one of which contains 3 fifty paisa coins and 2 one-rupee coins and the other contains 2 fifty paisa coins and 3 one rupee coins.

TLS Online TPP Program

#Question id: 21726

#Section 5: Bioprocess Engineering and Process Biotechnology

For a first order chemical reaction, the rate constant

TLS Online TPP Program

#Question id: 21727

#Section 5: Bioprocess Engineering and Process Biotechnology

In the reaction H2O2(aq) → H2O(l) + ½ O2(g), the initial concentration of H2O2 is 0.2546 M, and the initial rate of reaction is 9.32×10^–4 M s^–1. What will be [H2O2] at t = 35 s?

TLS Online TPP Program

#Question id: 21728

#Section 5: Bioprocess Engineering and Process Biotechnology

In the reaction A → products, we find that when [A] has fallen to half of its initial value, the reaction proceeds at the same rate as its initial rate. Is the reaction zero order, first order, or second order?

TLS Online TPP Program

#Question id: 21729

#Section 5: Bioprocess Engineering and Process Biotechnology

In the reaction, A → products, with the initial concentration [A]0 = 1.512 M, [A] is found to be 1.496 M at t = 30 s. With the initial concentration [A]0 = 2.584 M, [A] is found to be 2.552 M at t = 1 min. What is the order of this reaction?

TLS Online TPP Program

#Question id: 21730

#Section 5: Bioprocess Engineering and Process Biotechnology

In the first-order decomposition of dinitrogen pentoxide at 335 K,

N2O5(g) → 2 NO2(g) + ½ O2(g)

if we start with a 2.50-g sample of N2O5 at 335 K and have 1.50 g remaining after 109 s, 

(a) What is the value of the rate constant k? 

(b) What is the half-life of the reaction? 

TLS Online TPP Program

#Question id: 21731

#Section 5: Bioprocess Engineering and Process Biotechnology

The smog constituent peroxyacetyl nitrate (PAN) dissociates into peroxyacetyl radicals and NO2(g) in a first order reaction with a half-life of 32 min. 

If the initial concentration of PAN in an air sample is 2.7×10¹⁵ molecules/L, what will be the concentration 2.24 h later?