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#Question id: 15400


Inverse Laplace transform for 6s / (s+1)(s+2)(s+4) is

#Section 1: Engineering Mathematics
  1. _2e-t+ 6 e-2t + 4e-4t 
  2. -2e-t+ 6 e-2t - 4e-4t
  3. -2e-t+ 6e2t + 46-4t
  4. -2e-t+ 6e-2t + 4e4t