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#Question id: 15599


Find the positive real root of x3 - x - 3 = 0 using Newton-Raphson method. If the starting guess (x0) is 2, the numerical value of the root after two iterations (x2) is   (round off to two decimal places). 

#Section 1: Engineering Mathematics
  1. -
  2. -
  3. -
  4. -

Answer:- Option(s): 1.7-1.7


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