Practice Questions

  1. Home
  2. Free Resources
  3. Practice Questions
  4. 20696
TLS Online TPP Program

#Question id: 19485

The growth of S.cerevisiae on glucose under anaerobic conditions can be described by the following reaction:
C6H12O6 + aNH3 → 0.59 CH1.64N0.16O0.52 (biomass) + 0.43 C3H8O3 + 1.54CO2 + 1.3C2H5OH +0.036H2O
Determine the biomass (MW= 23.74) yield coefficient Yx/s

#Section 4: Fundamentals of Biological Engineering
  1. 0.078 g. g⁻¹
  2. 0.070 g. g⁻¹
  3. 0.068 g. g⁻¹
  4. 0.060 g. g⁻¹
More Questions
TLS Online TPP Program

#Question id: 3612

#Section 3: Genetics, Cellular and Molecular Biology

Multiple alleles control inheritance of
TLS Online TPP Program

#Question id: 3613

#Section 3: Genetics, Cellular and Molecular Biology

When a single gene influences more than one trait it is called
TLS Online TPP Program

#Question id: 3614

#Section 3: Genetics, Cellular and Molecular Biology

A gene showing codominance–
TLS Online TPP Program

#Question id: 3615

#Section 3: Genetics, Cellular and Molecular Biology

What are alleles?
TLS Online TPP Program

#Question id: 3616

#Section 3: Genetics, Cellular and Molecular Biology

If the parents are AO and BO genotypes for the ABO blood group, their children could include which of the following genotypes?
TLS Online TPP Program

#Question id: 3617

#Section 3: Genetics, Cellular and Molecular Biology

Alternate forms of a gene is called