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TLS Online TPP Program

#Question id: 19485

The growth of S.cerevisiae on glucose under anaerobic conditions can be described by the following reaction:
C₆H₁₂O₆ + aNH₃ → 0.59 CH1.64N0.16O0.52 (biomass) + 0.43 C3H8O3 + 1.54CO2 + 1.3C2H5OH +0.036H2O
Determine the biomass (MW= 23.74) yield coefficient Yx/s

#Section 4: Fundamentals of Biological Engineering

0.078 g. g⁻¹
0.070 g. g⁻¹
0.068 g. g⁻¹
0.060 g. g⁻¹

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TLS Online TPP Program

#Question id: 14869

#Section 1: Engineering Mathematics

is equal to

TLS Online TPP Program

#Question id: 14870

#Section 1: Engineering Mathematics

TLS Online TPP Program

#Question id: 14871

#Section 1: Engineering Mathematics

is equal to

TLS Online TPP Program

#Question id: 14872

#Section 1: Engineering Mathematics

is equal to

TLS Online TPP Program

#Question id: 14873

#Section 1: Engineering Mathematics

is equal to

TLS Online TPP Program

#Question id: 14874

#Section 1: Engineering Mathematics

The area under curve y for