TLS Online TPP Program

#Question id: 19486


The growth of S.cerevisiae on glucose under anaerobic conditions can be described by the following reaction:
C6H12O6 + aNH3 → 0.59 CH1.64N0.16O0.52 (biomass) + 0.43 C3H8O3 + 1.54CO2 + 1.3C2H5OH + 0.036H2
and determine the product yield coefficient Y etoh/s and determine coefficient a.

#Section 4: Fundamentals of Biological Engineering
  1. 0.57 g. g⁻¹, 0.078
  2. 0.33 g. g⁻¹, 0.094
  3. 0.45 g. g⁻¹, 0.086
  4. 0.44 g. g⁻¹, 0.056