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TLS Online TPP Program
#Question id: 14930
#Section 5: Bioprocess Engineering and Process Biotechnology
E. coli grows from 0.10 to 0.50 kg dry cell m-3 in 1 h. Assuming exponential growth during this period, evaluate the specific growth rate
TLS Online TPP Program
#Question id: 14931
#Section 5: Bioprocess Engineering and Process Biotechnology
E. coli grows from 0.10 to 0.50 kg dry cell m-3 in 1 h. Evaluate the doubling time during the exponential growth phase
TLS Online TPP Program
#Question id: 14932
#Section 5: Bioprocess Engineering and Process Biotechnology
E. coli grows from 0.10 to 0.50 kg dry cell m-3 in 1 h. How much time would be required to grow from 0.10 to 1.0 kg dry cell m-3? You may assume exponential growth during this period
TLS Online TPP Program
#Question id: 14933
#Section 5: Bioprocess Engineering and Process Biotechnology
E. coli was continuously cultured in a continuous stirred tank fermenter with a working volume of 1.0 I by chemostat. A medium containing 4.0 g1-1 of glucose as a carbon source was fed to the fermenter at a constant flow rate of 0.5 I h-1, and the glucose concentration in the output stream was 0.20 g1-1, The cell yield with respect to glucose YxS was 0.42 g dry cells per gram glucose. Determine the cell concentration in the output stream
TLS Online TPP Program
#Question id: 14934
#Section 5: Bioprocess Engineering and Process Biotechnology
E. coli was continuously cultured in a continuous stirred tank fermenter with a working volume of 1.0 I by chemostat. A medium containing 4.0 g1-1 of glucose as a carbon source was fed to the fermenter at a constant flow rate of 0.5 I h-1, and the glucose concentration in the output stream was 0.20 g I-1. The cell yield with respect to glucose YxS was 0.42 g dry cells per gram glucose. Determine specific growth rate
TLS Online TPP Program
#Question id: 14935
#Section 1: Engineering Mathematics
