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TLS Online TPP Program

#Question id: 36358

Which of the following statements is/are correct regarding SignalP ? 

#Section 7: Recombinant DNA technology and Other Tools in Biotechnology
  1. It  is a web-based program that predicts subcellular localization signals by using both neural networks and HMMs.
  2. The program is trained by three different training sets, namely, eukaryotes, Gram-negative bacteria and Gram-positive bacteria.
  3. The HMM-based analysis discriminates between signal peptides and the N-terminal transmembrane anchor segments required for insertion of the protein into the membrane.
  4. The program predicts both the signal peptides and the protease cleavage sites of the query sequence.
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TLS Online TPP Program

#Question id: 14319

#Section 5: Bioprocess Engineering and Process Biotechnology

Both Saccharomyces cerevisiae yeast and Zymomonas mobilis bacteria produce ethanol from glucose under anaerobic conditions without external electron acceptors. The biomass yield from glucose is 0.11 g g-1 for yeast and 0.05 g g-I for Z. mobilis. In both cases the nitrogen source is NH3. Both cell compositions are represented by the formula CH1.800.5N0.2. What is the yield of ethanol from glucose by Saccharomyces cerevisiae yeast?
TLS Online TPP Program

#Question id: 14320

#Section 5: Bioprocess Engineering and Process Biotechnology

Both Saccharomyces cerevisiae yeast and Zymomonas mobilis bacteria produce ethanol from glucose under anaerobic conditions without external electron acceptors. The biomass yield from glucose is 0.11 g g-1 for yeast and 0.05 g g-I for Z. mobilis. In both cases the nitrogen source is NH 3. Both cell compositions are represented by the formula CH 1.800.5N0.2. What is the yield of ethanol from glucose by Zymomonas mobilis bacteria?

TLS Online TPP Program

#Question id: 14321

#Section 5: Bioprocess Engineering and Process Biotechnology

Both Saccharomyces cerevisiae yeast and Zymomonas mobilis bacteria produce ethanol from glucose under anaerobic conditions without external electron acceptors. The biomass yield from glucose is 0.11 g g-1 for yeast and 0.05 g g-I for Z. mobilis. In both cases the nitrogen source is NH 3. Both cell compositions are represented by the formula CH 1.800.5N0.2. Compare actual yield with theoretical maximum for Zymomonas mobilis bacteria ?
TLS Online TPP Program

#Question id: 14322

#Section 5: Bioprocess Engineering and Process Biotechnology

Production of recombinant protein by a geneticallyengineered strain of Escherichia coli is proportional to cell growth. Ammonia is used as nitrogen source for aerobic respiration of glucose. The recombinant protein has an overall formula CHI.5500.31N0.25. The yield ofbiomass from glucose is measured at 0.48 g g-1; the yield of recombinant protein from glucose is about 20% that for cells. How much ammonia is required per gmol glucose?
TLS Online TPP Program

#Question id: 14323

#Section 5: Bioprocess Engineering and Process Biotechnology

Production of recombinant protein by a geneticallyengineered strain of Escherichia coli is proportional to cell growth. Ammonia is used as nitrogen source for aerobic respiration of glucose. The recombinant protein has an overall formula CHI.5500.31N0.25. The yield ofbiomass from glucose is measured at 0.48 g g-1; the yield of recombinant protein from glucose is about 20% that for cells. What is the oxygen demand per gmol glucose?
TLS Online TPP Program

#Question id: 14324

#Section 5: Bioprocess Engineering and Process Biotechnology

Production of recombinant protein by a geneticallyengineered strain of Escherichia coli is proportional to cell growth. Ammonia is used as nitrogen source for aerobic respiration of glucose. The recombinant protein has an overall formula CHI.5500.31N0.25. The yield of biomass from glucose is measured at 0.48 g g-1; the yield of recombinant protein from glucose is about 20% that for cells. If the biomass yield remains at 0.48 g g- l, how much change in oxygen requirement for wild-type E. coli unable to synthesise recombinant protein?