TLS Online TPP Program

#Question id: 11380


Which of the following is/are NOT valid explanation(s) for the observed pattern of species richness?

#XL - R Botany
  1. Older communities are more species rich.
  2. Large areas support more species.

  3. Absence of Natural enemies, area with more species richness
  4. Greater productivity permits existence of more species
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TLS Online TPP Program

#Question id: 34200

#XL - S Microbiology

A culture has a cell concentration of 1 × 109 cells/mL and a biomass yield coefficient (Yx/s) of 0.5 g biomass/g substrate. If 2 grams of substrate are consumed, calculate the biomass produced (in grams).

TLS Online TPP Program

#Question id: 34201

#XL - S Microbiology

In a chemostat, the dilution rate (D) is 0.5 h-1 and the specific growth rate (μ) of the organism equals the dilution rate. Calculate the residence time of the culture in minutes.

TLS Online TPP Program

#Question id: 34202

#XL - S Microbiology

If a culture starts with N0=2×106 cells and grows to N=1.6×107 cells, calculate the number of generations (n).

TLS Online TPP Program

#Question id: 34203

#XL - S Microbiology

For a bacterial species, the following parameters are known:
μmax=0.9 h−1
Ks=0.1 g/L
Substrate concentration S=0.1 g/L 
Calculate the specific growth rate μ.

TLS Online TPP Program

#Question id: 34204

#XL - S Microbiology

A bacterium has a 𝜇max​  of 1.2 h⁻¹ and exhibits a specific growth rate (𝜇) of 0.8 h⁻¹ when the substrate concentration 𝑆 is 0.4 g/L. Calculate the value of 𝐾𝑠​ .

TLS Online TPP Program

#Question id: 34205

#XL - S Microbiology

A continuous culture is maintained under steady-state conditions in a chemostat where the dilution rate equals the specific growth rate. If the maximum specific growth rate (μmax) of the organism is 0.8 h-1 and the substrate concentration at which the organism grows at this rate is 1.6 g/L, determine the substrate concentration (in g/L) at which the specific growth rate becomes 0.4 h-1. Assume Monod kinetics apply and Ks=0.4 g/L.