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#Question id: 3276


Which of these conditions are always true of populations evolving due to natural selection?

Condition 1: The population must vary in traits that are heritable.

Condition 2: Some heritable traits must increase reproductive success.

Condition 3: Individuals pass on most traits that they acquire during their lifetime.

#Unit 11. Evolution and Behavior
  1. Condition 1 only

  2. Condition 2 only

  3. Conditions 1 and 2

  4. Conditions 2 and 3

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TLS Online TPP Program

#Question id: 12166

#Unit 8. Inheritance Biology

If cross has made between the plant height 46cm and 10cm , then the F1 progeny shown 28cm . If the of this cross is 3QTL, then how much phenotypes will be formed?

TLS Online TPP Program

#Question id: 12165

#Unit 8. Inheritance Biology

If the environmental variance increases and all other variance components remain same , then what will be the effect on heritability?

TLS Online TPP Program

#Question id: 12164

#Unit 8. Inheritance Biology

What is the value of broad sense and narrow sense heritability respectively , if the given values of;
A) dominance genetic variance =0.4 , 
B) genic interaction variance =0.3,  
C) additive genetic variance =0.6, 
D) environmental variance=0.8,  
E) genetic−environmental interaction variance=0.3

TLS Online TPP Program

#Question id: 12163

#Unit 8. Inheritance Biology

A cross is made between the two pure line homozygous plant their height is 6cm and 2cm. the F1 progeny shows 6 cm height. the variations takes place in F2 progeny , which were made by 

TLS Online TPP Program

#Question id: 12162

#Unit 8. Inheritance Biology

Nilsson-Ehle’s cross obtained homozygous varieties of wheat that differed in color, he crossed a variety of wheat that possessed white kernels with a variety that possessed  red kernels and obtained the following results:

The following conclusions are made from the results obtained;

TLS Online TPP Program

#Question id: 12161

#Unit 8. Inheritance Biology

If a cross is made between  two plant heights  46cm and 10cm. The f2 Genotype has been shown;
I) AABBCC - 2) AABBCc – 3) AABbCc – 4) AaBbCc–  5) AaBbcc – 6) Aabbcc – 7) aabbcc –
Find out the 
i) phenotypic values of the given character 
ii) determining the no of polygenes involves and 
iii) what will be the no of QTL?