TLS Online TPP Program

#Question id: 910


Experiments on denaturation and renaturation after the reduction and reoxidation of the —S—S— bonds in the enzyme ribonuclease (RNase) have shown that:

#Unit 1. Molecules and their Interaction Relevant to Biology
  1. folding of denatured RNase into the native, active conformation, requires the input of energy in the form of heat.

  2. native ribonuclease does not have a unique secondary and tertiary structure.

  3. the completely unfolded enzyme, with all —S—S— bonds broken, is still enzymatically active.

  4. the primary sequence of RNase is sufficient to determine its specific secondary and tertiary structure.

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TLS Online TPP Program

#Question id: 5706

#Unit 8. Inheritance Biology

Species A has 2n = 16 chromosomes and species B has 2n = 14. How many chromosomes would be found in an allotriploid of these two species?

TLS Online TPP Program

#Question id: 5707

#Unit 8. Inheritance Biology

Which of the following statement is correct for human is heterozygous for inversion?

TLS Online TPP Program

#Question id: 5708

#Unit 8. Inheritance Biology

If non-disjunction occurs in meiosis I, which of the following scenario is most likely to occur?

TLS Online TPP Program

#Question id: 5709

#Unit 8. Inheritance Biology

What is probability of couple where male is karyotypically normal and the female in pericentric inversion in heterozygous condition produced child with disability if 50% chance of crossing over takes placed within pericentric inversion. (Note: Duplication and deletion in gamete will results  in disability)

TLS Online TPP Program

#Question id: 5732

#Unit 8. Inheritance Biology

Consider a plant, such as maize, heterozygous for a paracentric inversion. The inversion is very small and a synapsed inversion loop does not occur in any of the cells. Which of the following statement is correct?

TLS Online TPP Program

#Question id: 5735

#Unit 8. Inheritance Biology

Aneuploids may arise through nondisjunction, the failure of homologous chromosomes or sister chromatids to separate in meiosis. Following some statement are correct.

A)  Meiosis I non-disjunction leads to produce all gamete become aneuploidy

B) Meiosis II non-disjunction leads to produce half of gametes n+1 other half normal haploid

C) Meiosis I non-disjunction leads to produce half of gametes n+1 other half n-1

D) Either meiosis I or meiosis II non-disjunction leads to produce all aneuploidy gamete