Correct approaches to protein structure prediction-:

i. Homology modeling	a) Methods is the Rosetta program, formulated by David Baker. To satisfy the program’s computational needs, a volunteer network of ∼100,000 computers, known as Rosetta@home, provides the 500,000 or so hours of processing time required to generate a structure.
ii. Structural genomics	b) which seeks to determine the X-ray structures of all representative domains, is aimed at expanding this predictive technique. The identification of structural homology is likely to provide clues as to a protein’s function even with imperfect structure prediction.
iii. Threading	c) Is a computational technique that attempts to determine the unknown structure of a protein by ascertaining whether it is consistent with a known protein structure. It does so by placing the unknown protein’s residues along the backbone of a known protein structure and then determining whether the amino acid side chains of the unknown protein are stable in that arrangement
iv. Ab initio	d) Aligns the sequence of interest with the sequence of a homologous protein or domain of known structure—compensating for amino acid substitutions, insertions, and deletions—through modeling and energy minimization calculations.

#Question id: 5731

#Unit 8. Inheritance Biology

If an individual is heterozygous for this translocation, the consequence in meiosis will be as follows:

A) Segregation results in a + c in one Gametes and b + d in another gametes, have duplication and deficiency so unable to produce viable offspring

B) Segregation results in a + b in one Gametes and c + d in another gametes, have normal chromosome so all viable offspring produced

C) Segregation results in a + d in one Gametes with normal chromosome and b + c in another gametes contains translocation arrangement, all viable offspring produced

D) Segregation results in a + d in one Gametes with normal chromosome, will produced viable offspring while b + c in another gametes contains translocation arrangement, will produce non viable offspring.

#Question id: 5730

#Unit 8. Inheritance Biology

In a family, father is homozygous dominant (AA) for a gene A and his wife is homozygous for its ressive allele (aa) showing albino phenotype. It was surprising that their child showed the albino phenotype. Which of the following phenomenon can explain the phenotype?

#Question id: 5729

#Unit 8. Inheritance Biology

One chromosome in a plant has the sequence A B C D E F, and another has the sequence M N O P Q R. A reciprocal translocation between these chromosomes produced the following arrangement: A B C P Q R on one chromosome and M N O D E F on the other. If an individual is heterozygous for this translocation, the consequence in meiosis will be as follows:    

A. The two normal chromosomes and-two translocated chromosomes pair separately

B. Half of gametes produced from this meiosis are non-viable as they have deletions and duplications

C. In one of the cross configurations called "horizontal segregation" all gametes having normal or translocated chromosomes will not survive

D. The gametes having normal chromosomes only survive while all gametes having translocated chromosomes are non-viable, hence the translocations are used as crossover suppressors

Which of the following combinations best describes the meiotic consequences for the translocation described above?

#Question id: 5728

#Unit 8. Inheritance Biology

A phenotypically normal man carries a translocated chromosome that contains the entire long arm of chromosome 14, part of the short arm of chromosome 14, and most of the long arm of chromosome 21. The man also carries a normal chromosome 14 and a normal chromosome 21. If he marries a cytologically (and phenotypically) normal woman, there is many chance that the couple will produce phenotypically abnormal children? Which of the following is correct combination?

#Question id: 5727

#Unit 8. Inheritance Biology

Pairing occurs during the prophase of meiosis I, after the chromosomes have been duplicated. Centromere mention as 1, 2, 3 and 4

Which of the following is correct statement Types of disjunction in a translocation heterozygote during meiosis I.

A) Centromeres 1 and 3 go to one pole and centromeres 2 and 4 go to the other pole, producing non fuctional gametes.

B) Centromeres 1 and 2 go to one pole and centromeres 3 and 4 go to the other pole, producing viable gametes.

C) Centromeres 2 and 3 go to one pole and centromeres 1 and 4 go to the other pole, producing euploid gametes.

D) Centromeres 2 and 3 go to one pole and centromeres 1 and 4 go to the other pole, producing non viable gamete

#Question id: 5725

#Unit 8. Inheritance Biology

An individual is having an inversion in heterozygous condition. The regions on normal chromosome are marked as A, B, C, D, E, F, G while the chromosome having inversion has the regions as a, b, e, d, c, f, g. The diagram given below shows pairing of these two homologous chromosomes during meiosis and the site of a crossing over is indicated:

The following statements are given to describe the inversion and the consequence of crossing over shown in the above diagram:

A. This is a paracentric inversion

B. This will generate a dicentric and an acentric chromosome following separation of chromosomes after crossing over

C. This will generate two recombinant chromosomes with deletion and other parental chrmosome following separation of chromosomes after crossing over

D. 50 % gametes will be non viable due to deletion or duplication of chromatids

E. The gametes having recombinant chromatid or parental inversion chromatids will be non-viable