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#Question id: 12561


Given the following measurements, calculate the filtration fraction: glomerular capillary hydrostatic pressure = 50 mm Hg; Bowman’s space hydrostatic pressure = 15 mm Hg; colloid osmotic
pressure in the glomerular capillaries = 30 mm Hg; glomerular capillary filtration coefficient (Kf) = 12 ml/min/mm Hg; and renal plasma flow = 400 ml/min.

#Unit 7. System Physiology – Animal
  1. 0.15
  2. 0.20
  3. 0.25
  4. 0.30
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TLS Online TPP Program

#Question id: 5735

#Unit 8. Inheritance Biology

Aneuploids may arise through nondisjunction, the failure of homologous chromosomes or sister chromatids to separate in meiosis. Following some statement are correct.

A)  Meiosis I non-disjunction leads to produce all gamete become aneuploidy

B) Meiosis II non-disjunction leads to produce half of gametes n+1 other half normal haploid

C) Meiosis I non-disjunction leads to produce half of gametes n+1 other half n-1

D) Either meiosis I or meiosis II non-disjunction leads to produce all aneuploidy gamete

TLS Online TPP Program

#Question id: 5736

#Unit 8. Inheritance Biology

Two zygote in which one A is 44+XYY and another B is 44+XXX karyotype is best described by

TLS Online TPP Program

#Question id: 5726

#Unit 8. Inheritance Biology

Following diagram represents the sequence of genes in a normal chromosome of a plant species

CORRECT combination for chromosomal mutation using

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#Question id: 5723

#Unit 8. Inheritance Biology

An individual heterozygous for a reciprocal translocation possesses the following chromosomes

I-  nonviability                                  II – Viability        

III- only translocated chromosome     IV- only normal chromosome

V- one translocated another normal

Which of the following above chromosome constituent and feature in their gamete result from?

A- alternate       B- adjacent-1     C- adjacent-2

TLS Online TPP Program

#Question id: 23966

#Unit 8. Inheritance Biology

Deletion in short arm of chromosome number 4, that leads to cause syndrome;

TLS Online TPP Program

#Question id: 5734

#Unit 8. Inheritance Biology

Following is heterozygote for inversion?

Following some statement given for above abnormality?

A) There is a less probability of a crossover occurring within inversion region and producing an enviable cross over meiotic product.

B) Chromosomes that have engaged in crossing-over separate in the normal fashion, without the creation of a bridge

C) The crossover produces chromatids that contain duplication and a deletion for different parts of the chromosome results non viable gamete

D) Double cross over within inversion loop will be results all viable gamete of parental and recombinant