#Question id: 5725

An individual is having an inversion in heterozygous condition. The regions on normal chromosome are marked as A, B, C, D, E, F, G while the chromosome having inversion has the regions as a, b, e, d, c, f, g. The diagram given below shows pairing of these two homologous chromosomes during meiosis and the site of a crossing over is indicated:

The following statements are given to describe the inversion and the consequence of crossing over shown in the above diagram:

A. This is a paracentric inversion

B. This will generate a dicentric and an acentric chromosome following separation of chromosomes after crossing over

C. This will generate two recombinant chromosomes with deletion and other parental chrmosome following separation of chromosomes after crossing over

D. 50 % gametes will be non viable due to deletion or duplication of chromatids

E. The gametes having recombinant chromatid or parental inversion chromatids will be non-viable