TLS Online TPP Program

#Question id: 5008


Adaptive radiations can be a direct consequence of four of the following five factors. Select the exception.

#Unit 11. Evolution and Behavior
  1. vacant ecological niches

  2. genetic drift

  3. colonization of an isolated region that contains suitable habitat and few competitor species

  4. evolutionary innovation

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TLS Online TPP Program

#Question id: 5530

#Unit 5. Developmental Biology

 The cavity inside the blastula is called the

TLS Online TPP Program

#Question id: 6989

#Unit 5. Developmental Biology

Adult human bone:

TLS Online TPP Program

#Question id: 10210

#Unit 6. System Physiology – Plant

Some xanthophylls also participate in energy dissipation such as in light conversion of Violaxanthin to Zeaxanthin with antheraxanthin as the intermediate and vice-versa, which of the following statements is CORRECT?

a.) The conversion of Violaxanthin to Zeaxanthin a singlet oxygen is removed with the help of co-factor Ascorbate and violaxanthin de-epoxidase under high PPFD

b.) Zeaxanthin is oxidised into violaxanthin with the help of NADPH and oxygen under low PPFD

c.) Conversion of Violaxanthin to Zeaxanthin a singlet oxygen is removed with the help of NADPH and water under low PPFD

d.) Zeaxanthin is oxidised into violaxanthin in presence of enzyme known as violaxanthin de-epoxidase and co-factor Ascorbate under high PPFD

TLS Online TPP Program

#Question id: 11127

#Unit 7. System Physiology – Animal

As the receptor potential rises higher above threshold, which of the following best characterizes the new frequency of action potentials?

TLS Online TPP Program

#Question id: 5298

#Unit 8. Inheritance Biology

Four E. coli strains of genotype a+ b− are labeled 1, 2, 3, and 4. Four strains of genotype a− b+ are labeled 5, 6, 7, and 8. The two genotypes are mixed in all possible combinations and (after incubation) are plated to determine the frequency of a+ b+ recombinants. The following results are obtained, where M = many recombinants, L = low numbers of recombinants, and 0 = no recombinants. On the basis of these results, assign a sex type (either Hfr, F+, or F−) to each strain