TLS Online TPP Program

#Question id: 72


For the reaction catalyzed by the enzyme hexokinase: Glucose + ATP → glucose 6-phosphate + ADP the equilibrium constant, Keq, is 7.8 × 102. In living E. coli cells, [ATP] = 5 mM, [ADP] = 0.5 mM, [glucose] = 2 mM, and [glucose 6-phosphate] = 1 mM. Which of the following conclusions made on the basis of the above calculations is incorrect?

#SCPH05 I Biotechnology
  1. The reaction is therefore far from equilibrium.

  2. The cellular concentrations of the products are much lower and those of the reactants are much higher.

  3. The reaction therefore tends strongly to go to the right.

  4. The cellular concentrations of the products are much higher and those of the reactants are much lower.