TLS Online TPP Program

#Question id: 13090


To express a yeast gene in E. coli, your task is to design a strategy to insert the yeast gene into the bacterial plasmid. Below is a map of the area of the yeast genome surrounding the gene in which you are interested.

 
The distance between each tick mark placed on the line above is 100 bases in length
Below are the enzymes you can use, with their specific cut sites shown 5’-XXXXXX-3’ 3’-XXXXXX-5’

 
The plasmid is 5,000 bases long and the two farthest restriction enzyme sites are 200 bases apart. The plasmid has an ampicillin resistance gene somewhere on the plasmid distal from the restriction cut sites.
                              
You do the digestion of the insert and the vector and then ligate the two digestions together. You then transform the ligation into bacteria and select for ampicillin resistance. You get three colonies on your transformation plate. You isolate plasmid from each one and cut each plasmid with the enzyme XbaI. You then run your three digestions on an agarose gel and see the following patterns of bands. Describe what each plasmid actually was that was contained in each of the three colonies.
 
What is the Colony 3’s plasmid is;

#SCPH05 I Biotechnology
  1. Vector Alone (religated to itself)
  2. Yeast alone (religated to itself)
  3. Vector with Yeast Gene in the Right Orientation
  4. Vector with Yeast Gene in the Wrong Orientation
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TLS Online TPP Program

#Question id: 14930

#SCPH05 I Biotechnology

E. coli grows from 0.10 to 0.50 kg dry cell m-3 in 1 h. Assuming exponential growth during this period, evaluate the specific growth rate 

TLS Online TPP Program

#Question id: 14931

#SCPH05 I Biotechnology

E. coli grows from 0.10 to 0.50 kg dry cell m-3 in 1 h. Evaluate the doubling time during the exponential growth phase 

TLS Online TPP Program

#Question id: 14932

#SCPH05 I Biotechnology

 E. coli grows from 0.10 to 0.50 kg dry cell m-3 in 1 h. How much time would be required to grow from 0.10 to 1.0 kg dry cell m-3? You may assume exponential growth during this period 

TLS Online TPP Program

#Question id: 14933

#SCPH05 I Biotechnology

E. coli was continuously cultured in a continuous stirred tank fermenter with a working volume of 1.0 I by chemostat. A medium containing 4.0 g1-1 of glucose as a carbon source was fed to the fermenter at a constant flow rate of 0.5 I h-1, and the glucose concentration in the output stream was 0.20 g1-1, The cell yield with respect to glucose YxS was 0.42 g dry cells per gram glucose. Determine the cell concentration in the output stream 

TLS Online TPP Program

#Question id: 14934

#SCPH05 I Biotechnology

E. coli was continuously cultured in a continuous stirred tank fermenter with a working volume of 1.0 I by chemostat. A medium containing 4.0 g1-1 of glucose as a carbon source was fed to the fermenter at a constant flow rate of 0.5 I h-1, and the glucose concentration in the output stream was 0.20 g I-1. The cell yield with respect to glucose YxS was 0.42 g dry cells per gram glucose. Determine specific growth rate 

TLS Online TPP Program

#Question id: 14963

#I Life Science/ Life Sciences Group – I-V

Which antibiotics may be completely ineffective in treating a mycoplasmal infection?