TLS Online TPP Program

#Question id: 3875


Splicing of introns in nuclear mRNA primary transcripts requires:

#SCPH06 I Botany
  1. a guanine nucleoside or nucleotide.

  2. endoribonucleases.

  3. polynucleotide phosphorylase.

  4. small nuclear ribonucleoproteins (snurps).

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TLS Online TPP Program

#Question id: 17077

#SCPH28 | Zoology

Cells lacking Thymidine kinase if introduced into HAT medium which pathways will continue for nucleotide synthesis

TLS Online TPP Program

#Question id: 13089

#SCPH05 I Biotechnology

To express a yeast gene in E. coli, your task is to design a strategy to insert the yeast gene into the bacterial plasmid. Below is a map of the area of the yeast genome surrounding the gene in which you are interested.

 
The distance between each tick mark placed on the line above is 100 bases in length
Below are the enzymes you can use, with their specific cut sites shown 5’-XXXXXX-3’ 3’-XXXXXX-5’

 
The plasmid is 5,000 bases long and the two farthest restriction enzyme sites are 200 bases apart. The plasmid has an ampicillin resistance gene somewhere on the plasmid distal from the restriction cut sites.
                              
You do the digestion of the insert and the vector and then ligate the two digestions together. You then transform the ligation into bacteria and select for ampicillin resistance. You get three colonies on your transformation plate. You isolate plasmid from each one and cut each plasmid with the enzyme XbaI. You then run your three digestions on an agarose gel and see the following patterns of bands. Describe what each plasmid actually was that was contained in each of the three colonies.
 
What is the Colony 2’s plasmid is;

TLS Online TPP Program

#Question id: 9175

#SCPH28 | Zoology

In deep water, which of the following abiotic factors would most limit primary productivity?

TLS Online TPP Program

#Question id: 14268

#SCPH05 I Biotechnology

An activated-sludge waste treatment system is required to reduce the amount of BOD5 from 1000 mg/l to 20 mg/l at the exit. The sedimentation unit concentrates biomass by a factor of 3. Kinetic parameters are µm = 0.2 h-1 , Ks = 80 mg/l, kd = 0.01 h-1 , and Y M X/S = 0.5 g MLVSS/g BOD5. The flow of waste water is 10000 l/h and the size of the treatment basin is 50,000 l. What is the value of the solids residence time?

TLS Online TPP Program

#Question id: 3637

#SCPH28 | Zoology

Parents that are homozygous for different mutations a, b and c are crossed, producing offspring that are heterozygous as following

aa X bb        =  ab  (X)          

 bb X cc         =  bc  (Y)

aa X cc          =   ac  (Z)

If a and b belong to same locus but b and c belong to different locus then phenotype of heterozygote