#Question id: 391
#SCPH05 I Biotechnology
In a hospital laboratory, a 10.0 mL sample of gastric juice, obtained several hours after a meal, was titrated with 0.1 M NaOH to neutrality; 7.2 mL of NaOH was required. The patient’s stomach contained no ingested food or drink, thus assume that no buffers were present. What was the pH of the gastric juice?
#Question id: 402
#SCPH01 Biochemistry
If the DG'° of the reaction A -> B is –40 kJ/mol, under standard conditions the reaction:
#Question id: 402
#I Life Science/ Life Sciences Group – I-V
If the DG'° of the reaction A -> B is –40 kJ/mol, under standard conditions the reaction:
#Question id: 402
#SCPH05 I Biotechnology
If the DG'° of the reaction A -> B is –40 kJ/mol, under standard conditions the reaction:
#Question id: 402
#SCPH28 | Zoology
If the DG'° of the reaction A -> B is –40 kJ/mol, under standard conditions the reaction:
#Question id: 403
#SCPH01 Biochemistry
For the reaction A -> B, DG'° = –60 kJ/mol. The reaction is started with 10 mmol of A; no B is initially present. After 24 hours, analysis reveals the presence of 2 mmol of B, 8 mmol of A. Which is the most likely explanation?