TLS Online TPP Program

#Question id: 40193


Read the following statements:

Statement I: Obligate anaerobes cannot survive in the presence of oxygen because they lack the enzymes catalase and superoxide dismutase.

Statement II: Facultative anaerobes require oxygen for growth and cannot grow in its absence

#Applied Microbiology
  1. Both Statement I and Statement II are correct.
  2.  Both Statement I and Statement II are incorrect.
  3. Statement I is correct, but Statement II is incorrect
  4. Statement I is incorrect, but Statement II is correct
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TLS Online TPP Program

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#Bio-Informatics

Ultraviolet (UV) light can be used to estimate protein solution concentrations because

TLS Online TPP Program

#Question id: 402

#Biochemistry

If the DG'° of the reaction A -> B is –40 kJ/mol, under standard conditions the reaction:

TLS Online TPP Program

#Question id: 403

#Biochemistry

For the reaction A -> B, DG'° = –60 kJ/mol.  The reaction is started with 10 mmol of A; no B is initially present.  After 24 hours, analysis reveals the presence of 2 mmol of B, 8 mmol of A. Which is the most likely explanation?

TLS Online TPP Program

#Question id: 404

#Biochemistry

When a mixture of 3-phosphoglycerate and 2-phosphoglycerate is incubated at 25 °C with phosphoglycerate mutase until equilibrium is reached, the final mixture contains six times as much 2-phosphoglycerate as 3-phosphoglycerate.  Which one of the following statements is most nearly correct, when applied to the reaction as written?  (R = 8.315 J/mol·K; T = 298 K)  3-Phosphoglycerate -> 2-phosphoglycerate

TLS Online TPP Program

#Question id: 405

#Biochemistry

When a mixture of glucose 6-phosphate and fructose 6-phosphate is incubated with the enzyme phosphohexose isomerase (which catalyzes the interconversion of these two compounds) until equilibrium is reached, the final mixture contains twice as much glucose 6-phosphate as fructose 6-phosphate.  Which one of the following statements is best applied to this reaction outlined below? (R = 8.315 J/mol·K; T = 298 K) Glucose 6-phosphate -> fructose 6-phosphate

TLS Online TPP Program

#Question id: 406

#Biochemistry

Hydrolysis of 1 M glucose 6-phosphate catalyzed by glucose 6-phosphatase is 99% complete at equilibrium (i.e., only 1% of the substrate remains). Which of the following statements is most nearly correct? (R = 8.315 J/mol·K; T = 298 K)