TLS Online TPP Program

#Question id: 27067


Choose the correct statement regarding the stereochemistry of amino acid
1. 16 amino acid except (Thr, Ile, Cys, Gly) L Fischer projection is equal to S and D is equal to R configuration 
2. Thr, Ile is special case because of two chiral center exist in L – Ile/Thr – 2S,3R and D-Ile/Thr–2R,3S configuration  
3. Cys exiest in L- Cys – R & D- Cys – S configuration 
4. Gly is optically inactive 

#Section C (Domain-Specific Knowledge)
  1. 1 only      
  2.  2 & 3 
  3. 1, 2, & 3      
  4.  1, 2, 3, & 4
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TLS Online TPP Program

#Question id: 67

#Section C (Domain-Specific Knowledge)

When a region of DNA must be repaired by removing and replacing some of the nucleotides, what ensures that the new nucleotides are in the correct sequence?

TLS Online TPP Program

#Question id: 68

#Section C (Domain-Specific Knowledge)

Match the following functional groups given in column I with their respective representatives given in column II.

COLUMN ICOLUMN II
1. Anhydridea. RCOOR
2. Etherb. ROCOCH3
3. Acetylc. ROR
4. Amidod. RCOOCOR
5. Estere. RCONH2

TLS Online TPP Program

#Question id: 69

#Section C (Domain-Specific Knowledge)

Which of the following is the diastereomer of the following compound?

TLS Online TPP Program

#Question id: 70

#Section C (Domain-Specific Knowledge)

The dimensions of living cells are limited, on the lower end by the minimum number of biomolecules necessary for function, and on the upper end by the rate of diffusion of solutes such as oxygen. Except for highly elongated cells, they usually have lengths and diameters in the range of

TLS Online TPP Program

#Question id: 71

#Section C (Domain-Specific Knowledge)

Which of the following is not the priority rule for R, S Configuration?

TLS Online TPP Program

#Question id: 72

#Section C (Domain-Specific Knowledge)

For the reaction catalyzed by the enzyme hexokinase: Glucose + ATP → glucose 6-phosphate + ADP the equilibrium constant, Keq, is 7.8 × 102. In living E. coli cells, [ATP] = 5 mM, [ADP] = 0.5 mM, [glucose] = 2 mM, and [glucose 6-phosphate] = 1 mM. Which of the following conclusions made on the basis of the above calculations is incorrect?