TLS Online TPP Program

#Question id: 15155


In this problem we will explore some of the many ways that mutations in two different genes can interact to produce different Mendelian ratios. Consider a hypothetical insect species that has red eyes. Imagine mutations in two different unlinked genes that can, in certain combinations, block the formation of red eye pigment yielding mutants with white eyes. In principle, there are two different possible arrangements for two biochemical steps responsible for the formation of red eye pigment. The two genes might act in series such that a mutation in either gene would block the formation of red pigment. Alternatively, the two genes could act in parallel such that mutations in both genes would be required to block the formation of red pigment.

Further complexity arises from the possibility that mutations in either gene that lead to a block in enzymatic activity could be either dominant or recessive. If the crosses between a wild type insect with red eyes and a true breeding white eyed strain with mutations in both genes. Such considerations yield the Pathways in parallel with dominant mutations in both genes, determine the phenotype of the F1 progeny and the expected phenotypic ratio of red to white eyed insects in the F2.

#Unit 8. Inheritance Biology
  1. F1 will have white eyes

    Phenotypic ratio in F2 will be 15 white: 1 red

  2. F1 will have red eyes

    Phenotypic ratio in F2 will be 3 white: 13 red

  3. F1 will have white eyes

    Phenotypic ratio in F2 will be 1 white: 15 red

  4. F1 will have white eyes

    Phenotypic ratio in F2 will be 9 white: 7 red

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TLS Online TPP Program

#Question id: 12168

#Unit 8. Inheritance Biology

The proportion of the total phenotypic  variation that is due to genetic differences is known as 

TLS Online TPP Program

#Question id: 12167

#Unit 8. Inheritance Biology

If a cross is made between the two individuals such as,

The F1 shows the 512 individuals, contain the 2 individual shows maximum phenotype. 

i) No. of QTLs

ii) No. of polygenes involved

iii) No. of phenotypes in F2  generation

iv) No. of genotypes in F2 generation

Calculate the given different values;

TLS Online TPP Program

#Question id: 12166

#Unit 8. Inheritance Biology

If cross has made between the plant height 46cm and 10cm , then the F1 progeny shown 28cm . If the of this cross is 3QTL, then how much phenotypes will be formed?

TLS Online TPP Program

#Question id: 12165

#Unit 8. Inheritance Biology

If the environmental variance increases and all other variance components remain same , then what will be the effect on heritability?

TLS Online TPP Program

#Question id: 12164

#Unit 8. Inheritance Biology

What is the value of broad sense and narrow sense heritability respectively , if the given values of;
A) dominance genetic variance =0.4 , 
B) genic interaction variance =0.3,  
C) additive genetic variance =0.6, 
D) environmental variance=0.8,  
E) genetic−environmental interaction variance=0.3

TLS Online TPP Program

#Question id: 12163

#Unit 8. Inheritance Biology

A cross is made between the two pure line homozygous plant their height is 6cm and 2cm. the F1 progeny shows 6 cm height. the variations takes place in F2 progeny , which were made by