TLS Online TPP Program

#Question id: 15387


How might the results of Bernard Davis's U tube experiment have been different if each strain were only mutant for a single gene?

#Unit 8. Inheritance Biology
  1. There would be no difference.
  2. Transformation by small pieces of DNA could restore gene function.
  3. Conjugation would not be required to change the phenotype of the bacterial strains.
  4. B AND C
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TLS Online TPP Program

#Question id: 4350

#Unit 3. Fundamental Processes

Portions of the DNA sequences of normal and mutant b-globin genes are shown. The most plausible explanation for why the indicated mutation (changing an A to a G) results in the disease b-thalassemia is that the mutation

TLS Online TPP Program

#Question id: 4349

#Unit 3. Fundamental Processes

RNA Pol IV and Pol V

TLS Online TPP Program

#Question id: 4122

#Unit 3. Fundamental Processes

RNA Pol uses its active site, in a simple back-reaction, to catalyze the removal of an incorrectly inserted ribonucleotide. This phenomenon known as

TLS Online TPP Program

#Question id: 4121

#Unit 3. Fundamental Processes

The transition from the closed to the open complex involves structural changes in the enzyme and the opening of the DNA double helix to reveal the template and nontemplate strands. This “melting” involves

A. Isomerization reaction and it does not require energy derived from ATP hydrolysis

B. Isomerization is essentially irreversible and, once complete, typically guarantees that transcription will subsequently initiate

C. Positions –11 and -2, with respect to the transcription start site.

TLS Online TPP Program

#Question id: 4120

#Unit 3. Fundamental Processes

Which of the following homolog matching is incorrectly matched with thier respective subunits?

Bacterial

Archaea

RNAPI

RPAII

RPAIII

1.

B’

A’/A’’

RPA1

RPB1

RPC1

2.

B

K

RPA3

RPB2

RPC4

3.

aI

D

RPC5

RPB3

RPC5

4. 

aII

L

RPC9

RPB11

RPC9


TLS Online TPP Program

#Question id: 4119

#Unit 3. Fundamental Processes

Many eukaryotic genes contain a large number of exons. Correct splicing of such genes requires that neighboring exons be ligated to one another; if they are not, exons will be left out. One early proposal suggested that the splicing machinery bound to a splice site at one end of an intron and scanned through the intron to find the splice site at the other end. Such a scanning mechanism would guarantee that an exon was never skipped. This hypothesis was tested with one minigene with a duplicated 5ʹ splice site. Find diagram of the products you expect from minigene if the splicing machinery binds to a 5ʹ splice site and scans toward a 3ʹ splice site.