TLS Online TPP Program

#Question id: 5312


Why is it more difficult to identify eukaryotic genes than prokaryotic genes using genomic techniques?

#Unit 11. Evolution and Behavior
  1. The proteins are larger in eukaryotes than in prokaryotes.

  2. The coding portions of genes in eukaryotes are shorter than in prokaryotes.

  3. There are no start codons in eukaryotic genes.

  4. There are introns in eukaryotic genes.

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TLS Online TPP Program

#Question id: 5726

#Unit 8. Inheritance Biology

Following diagram represents the sequence of genes in a normal chromosome of a plant species

CORRECT combination for chromosomal mutation using

TLS Online TPP Program

#Question id: 5723

#Unit 8. Inheritance Biology

An individual heterozygous for a reciprocal translocation possesses the following chromosomes

I-  nonviability                                  II – Viability        

III- only translocated chromosome     IV- only normal chromosome

V- one translocated another normal

Which of the following above chromosome constituent and feature in their gamete result from?

A- alternate       B- adjacent-1     C- adjacent-2

TLS Online TPP Program

#Question id: 23966

#Unit 8. Inheritance Biology

Deletion in short arm of chromosome number 4, that leads to cause syndrome;

TLS Online TPP Program

#Question id: 5734

#Unit 8. Inheritance Biology

Following is heterozygote for inversion?

Following some statement given for above abnormality?

A) There is a less probability of a crossover occurring within inversion region and producing an enviable cross over meiotic product.

B) Chromosomes that have engaged in crossing-over separate in the normal fashion, without the creation of a bridge

C) The crossover produces chromatids that contain duplication and a deletion for different parts of the chromosome results non viable gamete

D) Double cross over within inversion loop will be results all viable gamete of parental and recombinant

TLS Online TPP Program

#Question id: 5733

#Unit 8. Inheritance Biology

In individuals heterozygous for a chromosome inversion, the homologous chromosomes form a loop in prophase I of meiosis.

Which of the following is effect of inversion?

A. A dicentric and an acentric chromosome in meiosis I as the chiasmata gets terminated when inversion includes centromere  

B. Appearance of deletion and duplication in both the cross over products chromosomes when centromere outside of inversion region  

C. All recombinant gamete are non-viable gametes when single crossing over within inverted region; irrespective to paracentric or pericentic inversion

D. Nonviable gametes are usually produced, resulting in a depression in observed recombination frequencies.

Which of the above statements are correct?

TLS Online TPP Program

#Question id: 5731

#Unit 8. Inheritance Biology

If an individual is heterozygous for this translocation, the consequence in meiosis will be as follows:

A) Segregation results in a + c in one Gametes and b + d in another gametes, have duplication and deficiency so unable to produce viable offspring

B) Segregation results in a + b in one Gametes and c + d in another gametes, have normal chromosome so all viable offspring produced

C) Segregation results in a + d in one Gametes with normal chromosome and b + c in another gametes contains translocation arrangement, all viable offspring produced

D) Segregation results in a + d in one Gametes with normal chromosome, will produced viable offspring while b + c in another gametes contains translocation arrangement, will produce non viable offspring.