TLS Online TPP Program

#Question id: 15913


The Smith-Waterman algorithm was developed for 

#SCPH05 I Biotechnology
  1. Local pairwise sequence alignment 
  2. Global pairwise sequence alignment 
  3. Multiple sequence alignment 
  4. Structural alignment 
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TLS Online TPP Program

#Question id: 2749

#SCPH05 I Biotechnology

Approximately what proportion of the human genome is made up of repetitive DNA sequences?

TLS Online TPP Program

#Question id: 8916

#SCPH06 I Botany

What do animals as diverse as corals and monkeys have in common?

TLS Online TPP Program

#Question id: 7287

#SCPH01 Biochemistry

Following statements are regarding to the the floral quartet model and the underlying ABCDE model of organ identity determination in Arabidopsis thaliana.

A. Five floral organ identities (sepals, petals, stamens, carpels, and ovules) are specified by the formation of floral organ-specific tetrameric complexes of MADS-domain transcription factors that bind to two nearby enhancer elements, forming a DNA loop in between.

B. A complex of two class A proteins (APETALA 1) and two class E proteins  (SEPALLATA) determines petal identity.

C. A complex of one class A protein, one class E protein, and one of each of the class B proteins (APETALA 3 and PISTILLATA) determines sepal identity.

D. A complex of one class E protein, two class B proteins, and one class C protein (AGAMOUS) determines stamen identity, while a complex of two class E proteins and two class C proteins determines carpel identity.D. A complex of one class E protein, two class B proteins, and one class C protein (AGAMOUS) determines stamen identity, while a complex of two class E proteins and two class C proteins determines carpel identity.

E. A complex of one class E protein, one class C protein, and one of each of the class D proteins (SHATTERPROOF and SEEDSTICK) controls ovule identity.

Which of the following combination are correct?

TLS Online TPP Program

#Question id: 588

#SCPH05 I Biotechnology

The initial velocity of an enzyme reaction (v0) describes

TLS Online TPP Program

#Question id: 15468

#SCPH05 I Biotechnology

In downstream processing of gluconic acid, concentrated fermentation broth containing 20% (w/w) gluconic acid is cooled in a heat exchanger prior to crystallisation. 2000 kg h-1 liquid leaving an evaporator at 90°C must be cooled to 6°C. Cooling is achieved by heat exchange with 2700 kg h-1 water initially at 2°C. The final temperature of the cooling water is 50°C. 
Assume (heat capacity of gluconic acid is 0.35 cal g-1 °C-1).
h (liquid water at 90°C = 376.9 kJ kg-1)
h (liquid water at 6°C = 25.2 kJ kg-1)
h (liquid water at 2°C = 8.4 kJ kg-1 )
h (liquid water at 50°C = 209.3 kJ kg-1)
h (gluconic acid at 90°C=0)
How much heat is removed to the cooling water?