TLS Online TPP Program

#Question id: 8944


Which two groups are most clearly represented in the Ediacaran fauna?

#SCPH06 I Botany
  1. I and II
  2. I and III
  3. II and IV
  4. II and V
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TLS Online TPP Program

#Question id: 70

#SCPH05 I Biotechnology

The dimensions of living cells are limited, on the lower end by the minimum number of biomolecules necessary for function, and on the upper end by the rate of diffusion of solutes such as oxygen. Except for highly elongated cells, they usually have lengths and diameters in the range of

TLS Online TPP Program

#Question id: 70

#SCPH06 I Botany

The dimensions of living cells are limited, on the lower end by the minimum number of biomolecules necessary for function, and on the upper end by the rate of diffusion of solutes such as oxygen. Except for highly elongated cells, they usually have lengths and diameters in the range of

TLS Online TPP Program

#Question id: 71

#SCPH05 I Biotechnology

Which of the following is not the priority rule for R, S Configuration?

TLS Online TPP Program

#Question id: 71

#SCPH06 I Botany

Which of the following is not the priority rule for R, S Configuration?

TLS Online TPP Program

#Question id: 72

#SCPH05 I Biotechnology

For the reaction catalyzed by the enzyme hexokinase: Glucose + ATP → glucose 6-phosphate + ADP the equilibrium constant, Keq, is 7.8 × 102. In living E. coli cells, [ATP] = 5 mM, [ADP] = 0.5 mM, [glucose] = 2 mM, and [glucose 6-phosphate] = 1 mM. Which of the following conclusions made on the basis of the above calculations is incorrect?

TLS Online TPP Program

#Question id: 72

#SCPH06 I Botany

For the reaction catalyzed by the enzyme hexokinase: Glucose + ATP → glucose 6-phosphate + ADP the equilibrium constant, Keq, is 7.8 × 102. In living E. coli cells, [ATP] = 5 mM, [ADP] = 0.5 mM, [glucose] = 2 mM, and [glucose 6-phosphate] = 1 mM. Which of the following conclusions made on the basis of the above calculations is incorrect?