Wild type E. coli metabolizes the sugar lactose by expressing the enzyme ß-galactosidase. You have isolated a mutant that you call lac1–, which cannot synthesize ß-galactosidase and cannot grow on lactose (Lac–). During an condition Lac– strain, called lac3–, is linked to the Tn5 insertion. From a strain carrying the Tn5 insertion and lac3– mutation you isolate an F’ that caries a region of the chromosome that includes both Tn5 and the linked Lac region. Introduce this F’ into an F– strain carrying lac1– by selecting for Kanr. These merodiploids express ß-galactosidase normally. If the merodiploid were Lac–, 

a) the two mutations lie in the different gene.

b) Both mutation are complement each other

c) the two mutations lie in the same gene.

d) Both of the mutations is dominant to wild type.

what could you conclude about the relationship between the lac3– and lac1– mutations from  these statements?

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#Question id: 15143

#I Life Science/ Life Sciences Group – I-V

Which one of the following is a depiction of the GenBank sequence entry format?

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#Question id: 15143

#SCPH05 I Biotechnology

Which one of the following is a depiction of the GenBank sequence entry format?

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#Question id: 15143

#SCPH05 I Biotechnology

Which one of the following is a depiction of the GenBank sequence entry format?

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#Question id: 15146

#SCPH01 Biochemistry

You have isolated a set of five yeast mutants that form dark red colonies instead of the usual white colonies of wild-type yeast. You cross each of the mutants to a wild-type haploid strain and obtain the results shown below;

What do these results tell you about each of the mutants?

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#Question id: 15146

#SCPH12 I Genetics

You have isolated a set of five yeast mutants that form dark red colonies instead of the usual white colonies of wild-type yeast. You cross each of the mutants to a wild-type haploid strain and obtain the results shown below;

What do these results tell you about each of the mutants?

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#Question id: 15147

#SCPH12 I Genetics

You have isolated a set of five yeast mutants that form dark red colonies instead of the usual white colonies of wild-type yeast. You cross each of the mutants to a wild-type haploid strain and obtain the results shown below;

you cross each haploid mutant strain to a different haploid mutant of the opposite mating type. From the results shown below deduce as much as you can about which mutations lie in the same gene. Clearly state any remaining ambiguities and suggest some general ways that the ambiguities might be resolved

a) That mutants 1 and 3 form one complementation group and are mutations in the same gene (gene A) 

b) That mutations 2 and 5 form a second complementation group and are mutations in a second gene (gene B).

c) That mutations 3 and 5 form a second complementation group and are mutations in a second gene (gene B).

d) The first ambiguity is whether mutant 4 has a mutation in gene A or B, or whether it represents a unique gene.

Which of the following is the correct prediction about mutants?