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#Question id: 18638


For unrooted trees, the number of unrooted tree topologies (NU) is ________

#SCPH01 Biochemistry
  1. NU = (2n− 5)!/2n−3(n− 5)!
  2. NU = (2n− 5)!/2n−3(n− 3)!
  3. NU = (2n− 5)!/2−2(n− 3)!
  4. NU = (2n− 5)!/2n(n− 3)!

Answer:- Option(s): 2


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