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TLS Online TPP Program

#Question id: 21246

The correct sequence of events involved in phototransduction in rods and cones in response to light is:

#Unit 7. System Physiology – Animal
  1. activation of transducin, decreased release of glutamate, structural changes in rhodopsin, closure of Na + channels, and decrease in intracellular cGMP.
  2. decreased release of glutamate, activation of transducin, closure of Na + channels, decrease in intracellular cGMP, and structural changes in rhodopsin.
  3. structural changes in rhodopsin, decrease in intracellular cGMP, decreased release of glutamate, closure of Na + channels, and activation of transducin.
  4. structural changes in rhodopsin, activation of transducin, decrease in intracellular cGMP, closure of Na + channels, and decreased release of glutamate.
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TLS Online TPP Program

#Question id: 7768

#Unit 5. Developmental Biology

The insulin signaling pathway inhibits the synthesis of the Foxo transcription factor proteins that would otherwise increase cellular longevity. Downregulation of the insulin signaling pathway has several other functions, choose right one
TLS Online TPP Program

#Question id: 13165

#Unit 5. Developmental Biology

One of the main ways by which the insulin signaling pathway might function to lower longevity is to activate mTORC1, a protein kinase complex that promotes the translation of mRNA into proteins in response to nutrients and hormones, select incorrect statement;
TLS Online TPP Program

#Question id: 14706

#Unit 5. Developmental Biology

Match the types of cell movement during gastrulation
TLS Online TPP Program

#Question id: 14707

#Unit 5. Developmental Biology

Which of the following organ belongs to the internal layer of gastrula?
TLS Online TPP Program

#Question id: 14708

#Unit 5. Developmental Biology

Difference between gastrulation in Xenopus and sea urchin;
I. In Xenopus, formation of blastopore: mesoderm and endoderm move inside by involution over blastopore lip.
II. In sea urchin, formation of blastopore: mesodermal cells migrate into the interior; endoderm moves inside by invagination of the epithelial sheet.
TLS Online TPP Program

#Question id: 14709

#Unit 5. Developmental Biology

Choose right statement about cleavage pattern and gastrulation movements;
1.At the end of cleavage the animal embryo is essentially a closed sheet of cells, which is often in the form of a sphere enclosing a fluid-filled interior. Gastrulation, strictly the formation of the gut, converts this sheet into a solid three-dimensional embryonic animal body. 
2.During cleavage, cells move into the interior of the embryo, and the regions of endoderm. and mesoderm. which were originally adjacent in the cell sheet, take up their appropriate positions in the embryo.
3. Gastrulation results from a well- defined spatio-temporal pattern of change in cell shape, cell movement, and change in cell adhesiveness, the main forces of which are generated by localized contractions.