TLS Online TPP Program

#Question id: 5395


The arithmetic mean of a set of 50 numbers is 38 . If two numbers, namely ,45 and 55, are discarded , the mean of the remaining set of numbers is:

#General Aptitude
  1. 36.5  

  2. 37 

  3. 37.2      

  4. 37.5

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TLS Online TPP Program

#Question id: 14998

#Unit 8. Inheritance Biology

You set up a monohybrid cross between true breeding round winged and true breeding oval winged insects. Your F1 offspring have round wings, and you collect the following numbers of F2: Round wings: 302; Oval wings: 86. Which of the following statements is NOT correct?

TLS Online TPP Program

#Question id: 14999

#Unit 8. Inheritance Biology

I know that black coat color in mice is dominant to albino. Black mice get a higher price at the pet store so I am disappointed when I cross a black mouse with an albino mouse and get 6 albino and 2 black mice in the litter. I expected all black. What mistake did I make?

TLS Online TPP Program

#Question id: 15000

#Unit 8. Inheritance Biology

I do a chi square analysis of the offspring from my cross of a black mouse and albino mouse. If the black mouse was heterozygous I should have expected a 1:1 ratio, and I got 6 albino and 2 black mice. What is my chi square value?

TLS Online TPP Program

#Question id: 15001

#Unit 8. Inheritance Biology

You cross true breeding lizards that are either green or albino and discover that all the offspring are striped green and white. Which is the most likely result if you cross two striped lizards?

TLS Online TPP Program

#Question id: 15002

#Unit 8. Inheritance Biology

If you performed a dihybrid cross and found that your results were significantly different from the 9:3:3:1 ratio, what would you suspect?

TLS Online TPP Program

#Question id: 15659

#Unit 8. Inheritance Biology

You calculate map distances between genes A, B, and C based on all pairwise dihybrid crosses. When you perform the trihybrid cross to verify your results, you discover that, despite analysis of a very large number of progeny, you have only about half as many double crossover progeny as you expect. Which explanation is the most reasonable?