TLS Online TPP Program

#Question id: 3592


In garden peas, tall (T) is dominant to short (t), Purple Flowers are (P) dominant to white flowers (p), Axial flowers (A) are dominant to terminal flowers (a), and yellow seeds (G) are dominant to green seeds (g). An individual from a true breeding line of tall, purple flowered, axial-flowered, yellow seeded pea plants is mated to an individual from a true breeding line of short, white flowered, terminal-flowered, green-seeded plants. The F1 are allowed to self-fertilize and produce an F2. What proportion of the F2 is expected to exhibit purple flowers and yellow seeds?

#Section 3: Genetics, Cellular and Molecular Biology
  1. 1/4             

  2. 3/4         

  3. 81/244   

  4. 9/16

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TLS Online TPP Program

#Question id: 14305

#Section 5: Bioprocess Engineering and Process Biotechnology

Ethanol is to be used as a substrate for single-cell protein production in a chemostat. The available equipment can achieve an oxygen transfer rate of 10 g O2/l of liquid per hour. Assume the kinetics of cell growth on ethanol is of the Monod type, with µm = 0.5 h–1, Ks = 30 mg/l, YX/S = 0.5 cells/g ethanol, and YO2/S = 2 g O2/g EtOH. We wish to operate the chemostat with an ethanol concentration in the feed of 22 g/L. We also wish to maximize the biomass productivity and minimize the loss of unused ethanol in the effluent. Determine the required dilution rate

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TLS Online TPP Program

#Question id: 14306

#Section 5: Bioprocess Engineering and Process Biotechnology

Pseudomonas putida with mm = 0.5 h-1 is cultivated in a continuous culture under aerobic conditions where D = 0.28 h-1 . The carbon and energy source in the feed is lactose with aconcentration of S0 = 2 g/l. The effluent lactose concentration is desired to be S = 0.1 g/l. If the growth rate is limited by oxygen transfer, by using the following information:

Determine the steady-state biomass concentration (X)

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TLS Online TPP Program

#Question id: 14307

#Section 5: Bioprocess Engineering and Process Biotechnology

Pseudomonas putida with mm = 0.5 h-1 is cultivated in a continuous culture under aerobic conditions where D = 0.28 h-1 . The carbon and energy source in the feed is lactose with aconcentration of S0 = 2 g/l. The effluent lactose concentration is desired to be S = 0.1 g/l. If the growth rate is limited by oxygen transfer, by using the following information


Determine specific rate of oxygen consumption (qO2 ).

TLS Online TPP Program

#Question id: 14308

#Section 5: Bioprocess Engineering and Process Biotechnology

Pseudomonas putida with µm = 0.5 h-1 is cultivated in a continuous culture under aerobic conditions where D = 0.28 h-1 . The carbon and energy source in the feed is lactose with aconcentration of S0 = 2 g/l. The effluent lactose concentration is desired to be S = 0.1 g/l. If the growth rate is limited by oxygen transfer, by using the following information:


What should be the oxygen-transfer coefficient (kLa) in order to overcome oxygentransfer limitation (i.e., CL = 2 mg/l)? ___________________

TLS Online TPP Program

#Question id: 14309

#Section 5: Bioprocess Engineering and Process Biotechnology

Glucose is converted to ethanol by immobilized yeast cells entrapped in gel beads. The specific rate of ethanol production is: qP = 0.2 g ethanol/g-cell-h. The effectiveness factor for an average bead is 0.8. Each bead contains 50 g/L of cells. The voids volume in the column is 40%. Assume growth is negligible (all glucose is converted into ethanol). The feed flow rate is F = 400 l/h and glucose concentration in the feed is S0i = 150 g glucose/l. The diameter of the column is 1 m and the yield coefficient is about 0.49 g ethanol/g glucose. The column height is 4 m. What is the glucose conversion at the exit of the column?

TLS Online TPP Program

#Question id: 14310

#Section 5: Bioprocess Engineering and Process Biotechnology

Glucose is converted to ethanol by immobilized yeast cells entrapped in gel beads. The specific rate of ethanol production is: qP = 0.2 g ethanol/g-cell-h. The effectiveness factor for an average bead is 0.8. Each bead contains 50 g/L of cells. The voids volume in the column is 40%. Assume growth is negligible (all glucose is converted into ethanol). The feed flow rate is F = 400 l/h and glucose concentration in the feed is S0i = 150 g glucose/l. The diameter of the column is 1 m and the yield coefficient is about 0.49 g ethanol/g glucose. The column height is 4 m. What is the ethanol concentration in the exit stream?

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