Please arrange the following steps about ELIZA (Enzyme-linked immunosorbent assay) in chronological order

i. incubate with antibody-enzyme complex that binds primary antibody

ii. coat surface with antigen, block unoccupied sites with nonspecific protein

iii. add substrate, formation of colored product indicates presence of specific antigen

iv. incubate with primary antibody against specific antigen

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#Question id: 14251

#Section 5: Bioprocess Engineering and Process Biotechnology

Yeast cells are recovered from a fermentation broth by using a tubular centrifuge. Sixty percent (60%) of the cells are recovered at a flow rate of 12 l/min with a rotational speed of 4000 rpm. Recovery is inversely proportional to flow rate. a. To increase the recovery of cells to 95% at the same flow rate, what should be the rpm of the centrifuge?

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TLS Online TPP Program

#Question id: 14252

#Section 5: Bioprocess Engineering and Process Biotechnology

Yeast cells are recovered from a fermentation broth by using a tubular centrifuge. Sixty percent (60%) of the cells are recovered at a flow rate of 12 l/min with a rotational speed of 4000 rpm. Recovery is inversely proportional to flow rate. At a constant rpm of 4000 rpm, what should be the flow rate to result in 95% cell recovery?

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#Question id: 14253

#Section 5: Bioprocess Engineering and Process Biotechnology

Hybridoma cells immobilized on surfaces of Sephadex beads are used in a packed column for production of monoclonoal antibodies (Mab). Hybridoma concentration is approximately X = 5 g/l in the bed. The flow rate of the synthetic medium and glucose concentration are Q = 2 l/h and S0 = 40 g/l, respectively. The rate constant for Mab formation is k = 1 gX/l-d. Assume that there are no diffusion limitations and glucose is the rate limiting nutrient.  Determine the volume of the packed bed for 95% glucose conversion. Bed diameter is D0 = 0.2 m. Neglect the growth of the hybridomas and assume first order kinetics. 

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#Question id: 14254

#Section 5: Bioprocess Engineering and Process Biotechnology

Hybridoma cells immobilized on surfaces of Sephadex beads are used in a packed column for production of monoclonoal antibodies (Mab). Hybridoma concentration is approximately X = 5 g/l in the bed. The flow rate of the synthetic medium and glucose concentration are Q = 2 l/h and S0 = 40 g/l, respectively. The rate constant for Mab formation is k = 1 gX/l-d. Assume that there are no diffusion limitations and glucose is the rate limiting nutrient.  Determine the height of the packed bed for 95% glucose conversion. Bed diameter is D0 = 0.2 m. Neglect the growth of the hybridomas and assume first order kinetics. 

TLS Online TPP Program

#Question id: 14255

#Section 5: Bioprocess Engineering and Process Biotechnology

Hybridoma cells immobilized on surfaces of Sephadex beads are used in a packed column for production of monoclonoal antibodies (Mab). Hybridoma concentration is approximately X = 5 g/l in the bed. The flow rate of the synthetic medium and glucose concentration are Q = 2 l/h and S0 = 40 g/l, respectively. The rate constant for Mab formation is k = 1 gX/l-d. Assume that there are no diffusion limitations and glucose is the rate limiting nutrient.  If Yp/s is 4 mg Mab/g glu, determine the effluent Mab concentration of the system?

TLS Online TPP Program

#Question id: 14256

#Section 5: Bioprocess Engineering and Process Biotechnology

Hybridoma cells immobilized on surfaces of Sephadex beads are used in a packed column for production of monoclonoal antibodies (Mab). Hybridoma concentration is approximately X = 5 g/l in the bed. The flow rate of the synthetic medium and glucose concentration are Q = 2 l/h and S0 = 40 g/l, respectively. The rate constant for Mab formation is k = 1 gX/l-d. Assume that there are no diffusion limitations and glucose is the rate limiting nutrient.  If Yp/s is 4 mg Mab/g glu, determine productivity of the system? __________________